The following information will help us with this problem:
![\sqrt[m]{x^n} = x^{\frac{n}{m}](https://tex.z-dn.net/?f=%5Csqrt%5Bm%5D%7Bx%5En%7D%20%3D%20x%5E%7B%5Cfrac%7Bn%7D%7Bm%7D)
When we use that information in the context of this problem, we can find:
![\sqrt[4]{15^7} = 15^{\frac{7}{4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B15%5E7%7D%20%3D%2015%5E%7B%5Cfrac%7B7%7D%7B4%7D%7D)
Thus, a = 15, b = 7, and c = 4.
Answer:
1) 5 2) 6 3) 1.25 or -1.75
Step-by-step explanation:
1. x^2 - 25 = 0
x^2 - 25 = 0
First, add 25 to both sides!
x^2 = 25
Now square root both sides.
x = 5
2. (x-2)^2 = 16
First, square root both sides.
(x-2) = 4
Add 2 on both sides.
(x) = 6
x = 6
3. Quadratic Formula = -b ± 
/ 2a
Substitute in:
-6 ±
/ 2(2)
-6±
/ 4
Both forms:
-6 + 
/ 4
5 / 4 = 1.25
Negative:
-6 - 1 / 4
-7 / 4 = -1.75
Answer:
f(x) = 4x^2 +2,
is the function
Step-by-step explanation:
if i get this wrong imma tie a brick to my feet and jump in the ocean
Neither P, nor A are on the sketch
I guess P is the upper right corner of the rectangle
and A=(0,1)
P belongs to the line going through (1,0) and B(0,y)
<span>but we don't know the y-coordinate of B </span>
<span>the triangle is right and isosceles, so pythagoras a²+a²=2² ... 2a²=4 ... a²=2 ... a=sqrt2 </span>
now look at the right triangle BOA
<span>his hypotenuse is AB=sqrt2 and the <span>the kathete</span> OA is 1 </span>
so y²+1²=(sqrt2)² ... y²+1=2 ... y²=1.. y=1
so the coordinates of B are (0,1)
the line going through (1,0) and (0,1) is L(x)=-x+1
P belongs to this line, so the coordinates of P are P(x,-x+1) (0<x<1)
b) so if that's P, the height of the rectangle is -x+1 and the width=2x
<span>so its area A(x)=2x*(-x+1)= -2x²+2x
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
28/4 = 7,
36/4 = 9,
Place the 7 over the 9 and you get 7/9!
