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3 years ago

Someone can help me ???

Chemistry

2 answers:

Oxana [17]3 years ago

7 0

The correct option is (a) Fruit salad.

As one cannot mix all the veges (or whatever you are using ) uniformly everywhere.

Tresset [83]3 years ago

6 0

C?? Think that is right

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"When elements are arranged in order of increasing atomic number, there is a periodic repetition of their physical and chemical

matrenka [14]

Answer: periodic law.

Justification:

1) Although Mendeleev formulated the modern periodic table, ordering the elements according to their physical and chemical properties, there is not such law as Meneleev's Law.

2) The Pauli exclusion principle states that two electrons on an atom cannot have the same 4 quantum numbers, which drives to the fact that only two electrons can stay in the same orbital, each with opposite spin numbers.

3) Hund's rule states that the electrons with the same energy level will occupy the orbitals with the same spin before adding the electrons with the opposite spin.

4) Indeed the periodic law <span>states that the elements are arranged in order of increasing atomic number, and there is a periodic repetition of their physical and chemical properties.</span>

6 0

3 years ago

Read 2 more answers

1) In 1.31 g of a chloride of titanium, there is 0.528 g of titanium. What is the empirical formula of this titanium chloride?

kozerog [31]

Answer:

TiCl2

Explanation:

Mass of the chloride of titanium= 1.31 g

Mass of titanium= 0.528 g

Therefore mass of chlorine = 1.31-0.528 = 0.782 g

To determine the empirical formulae of the titanium chloride, divide the mass of each element by its relative atomic mass and divide through by the lowest ratio.

Ti- 0.528/48 = 0.011, Cl- 0.782/35.5 = 0.022

Ti- 0.011/0.011 , Cl- 0.022/0.011

Ti- 1, Cl-2

Hence the required empirical formula is TiCl2

5 0

3 years ago

The decomposition of \rm XY is second order in \rm XY and has a rate constant of6.96Ã10â3M^{-1} \cdot s^{-1} at a certain temper

LUCKY_DIMON [66]

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

Half life for second order kinetics is given by:

$t_{1/2}=\frac{1}{k\times a_0}$

k = rate constant =?

$a_0$ = initial concentration

a = concentration left after time t

Integrated rate law for second order kinetics is given by:

$\frac{1}{a}=kt+\frac{1}{a_0}$

a) Initial concentration of XY = $a_o=0.100 M$

Rate constant of the reaction = k = $6.96\times 10^{-3} M^{-1} s^{-1}$

Half life of the reaction is:

$t_{1/2}=\frac{1}{6.96\times 10^{-3} M^{-1} s^{-1}\times 0.100 M}$

$=1,436.78 s$

1,436.78 seconds is the half-life for this reaction.

b) Initial concentration of XY = 0.100 M

Final concentration after time t = 12.5% of 0.100 M = 0.0125 M

$\frac{1}{0.0125 M}=6.96\times 10^{-3} M^{-1} s^{-1}\times t+\frac{1}{0.100M}$

Solving for t;

t = 10,057.47 seconds

In 10,057.47 seconds the concentration of XY will become 12.5% of its initial concentration.

c) Initial concentration of XY = 0.200 M

Final concentration after time t = 12.5% of 0.200 M = 0.025 M

$\frac{1}{0.025 M}=6.96\times 10^{-3} M^{-1} s^{-1}\times t+\frac{1}{0.200M}$

Solving for t;

t = 5,028.73 seconds

In 5,028.73 seconds the concentration of XY will become 12.5% of its initial concentration.

d) Initial concentration of XY = 0.160 M

Final concentration after time t = $6.20\times 10^{-2} M$

$\frac{1}{6.20\times 10^{-2} M}=6.96\times 10^{-3} M^{-1} s^{-1}\times t+\frac{1}{0.200M}$

Solving for t;

t = 1,419.40 seconds

In 1,419.40 seconds the concentration of XY will become $6.20\times 10^{-2} M$ .

e) Initial concentration of $SO_2Cl_2= 0.050 M$

Final concentration after time t = x

t = 55.0 s

$\frac{1}{x}=6.96\times 10^{-3} M^{-1} s^{-1}\times 55.0 s+\frac{1}{0.050 M}$

Solving for x;

x = 0.04906 M

The concentration after 55.0 seconds is 0.04906 M.

f) Initial concentration of XY= 0.050 M

Final concentration after time t = x

t = 500 s

$\frac{1}{x}=6.96\times 10^{-3} M^{-1} s^{-1}\times 500 s+\frac{1}{0.050 M}$

Solving for x;

x = 0.04259 M

The concentration after 500 seconds is 0.0.04259 M.

7 0

3 years ago

Water is placed in a graduated cylinder and the volume is recorded as 43.5 ml. a homogeneous sample of metal pellets with a mass

natulia [17]

Density = mass /volume of the body. mass = 10.88 g, volume of the liquid displaced= 49.4-43.5=5.9 ml.

density = 10.88/5.9=1.844 g/ml~1.84 g/ml

The volume displaced is exactly the same as that of the body (The Eureka fro Archimedes!)

7 0

3 years ago

DNA bases are attached to _____.

horsena [70]

Answer:

sugar molecules......

8 0

3 years ago