Question

When the following two solutions are mixed:

Answer 1

Answer:

For Part A: The spectator ions are $Fe^{3+}\text{ and }CO_3^{2-}$ and the ions that react are $K^+\text{ and }NO_3^-$

For Part B: The net ionic equation is given below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

• For Part A:

The chemical equation for the reaction of iron (III) nitrate and potassium carbonate is given as:

$2Fe(NO_3)_3(aq.)+3K_2CO_3(aq.)\rightarrow 6KNO_3(aq.) + Fe_2(CO_3)_3(s)$

Ionic form of the above equation follows:

$2Fe^{3+}(aq.)+2NO_3^-(aq.)+3K^+(aq.)+3CO_3^{2-}(aq.)\rightarrow 6K^+(aq.)+6NO_3^+(aq.)+Fe_2(CO_3)_3(s)$

As, potassium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$2Fe^{3+}(aq.)+CO_3^{2-}(aq.)\rightarrow Fe_2(CO_3)_3(s)$

Hence, the spectator ions are $Fe^{3+}\text{ and }CO_3^{2-}$ and the ions that react are $K^+\text{ and }NO_3^-$

• For Part B:

The chemical equation for the reaction of sulfuric acid and barium hydroxide is given as:

$Ba(OH)_2(aq.)+H_2SO_4(aq.)\rightarrow BaSO_4(s)+2H_2O(l)$

Ionic form of the above equation follows:

$Ba^{2+}(aq.)+2OH^-(aq.)+2H^+(aq.)+SO_4^{2-}(aq.)\rightarrow BaSO_4(s)+2H_2O(l)$

All the ions are present in this reaction. Thus, no ion is considered as spectator ions.

Answer 2

Answer:

PartA:

  spectator ions: K+ and NO3-

  ions that react: Fe+ and CO2-3

Explanation: