Answer is: 18 moles of lead(II)-nitrate.
Balanced chemical reaction:
3Pb(NO₃)₂ + 2AlCl₃ → 2Al(NO₃)₃ + 3PbCl₂.
n(Al(NO₃)₃) = 12 mol.
From chemical reaction: nAl(NO₃)₃) : n(Pb(NO₃)₂) = 2 : 3.
n(Pb(NO₃)₂) = 3 · 12 mol ÷ 2.
n(Pb(NO₃)₂) = 18 mol; amount of substance.
Al(NO₃)₃ is aluminium nitrate.
AlCl₃ is aluminium chloride.
Maybe use flash cards for them to understand or look up periodic table on line and show them.
Hey there:
density = 11.3 g/cm³
mass = 15,1 g
Therefore:
D = m / V
11.3 = 15.1 / V
V = 15.1 / 11.3
V = 1.336 cm³
Answer:
38.4 atm
Explanation:
Data obtained from the question include:
V1 (initial volume) = 3200 L
P1 (initial pressure) = 3.00 atm
V2 (final volume) = 250.0 L
P2 (final pressure) = ?
Using Boyle's law equation P1V1 = P2V2, the final pressure can be obtained as follow:
P1V1 = P2V2
3 x 3200 = P2 x 250
Divide both side by 250
P2 = 3 x 3200/250
P2 = 38.4 atm
Therefore, the pressure of the gas if ethylene is supplied by a 250.0 L tank is 38.4 atm
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