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valentinak56 [21]
3 years ago
9

How can I find the angular position in radians of the minute hand of a clock at 5:00, 7:15, an 3:35?

Mathematics
1 answer:
sveticcg [70]3 years ago
8 0
A) 5:00 
<span>At 00 minutes, the minute hand is point straight up. That is one quarter turn of the entire circle. One-fourth of 2π radians is 1/2 π, or π/2 </span>

b) 7:15 
At 15 minutes, the minute hand is pointing straight to the right, along the imaginary positive x-axis, so it has turned through none of the circle. 0 radians.

c) 3:30 
<span>This one isn't as clean as the others. Let's first find the 35 minute position: it occurs at hour number 7. Identify that measuring from 3 (positive x-axis, measuring counter clockwise) you have to turn through 40 minutes worth of clock. 40 minutes represents 40/60 of an entire clock, which reduces to 2/3. 2/3 of all the radians in a circle (2π of them) is 4/3π, or 4π/3. 

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
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600 *10=6000 if each of these are of 10

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StartFraction 12 minus 3 y Over 2 EndFraction plus y StartFraction 2 y minus 4 Over y EndFraction for y = 3.
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Answer:
Step-by-step explanation:
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m represents slope
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m = 1/2
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The slope intercept form of the equation of a straight line is expressed as
y = mx + c
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7 0
3 years ago
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Please help me with this :)<br>If fake answer, then will be reported!​
arsen [322]

Answer:

10 miles less

Step-by-step explanation:

To get the direct distance first, we use the pythagorean theorem. Distance from Ferris to Butte directly would be the hypotenuse. By solving for the hypotenuse, we have 25 miles. Now the distance used previously is 35 mile. Hence, it (35 - 25 = 10 ) miles less.

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The ammunition storage room has 10 feet between the floor and the ceiling. Each box of ammunition is 10 feet tall. Each crate of
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Answer:

the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.

Step-by-step explanation:

i) the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches

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240 as a percentage
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Answer:

240%

Step-by-step explanation:

240 / 100 Answer: 240%

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