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valentinak56 [21]
4 years ago
9

How can I find the angular position in radians of the minute hand of a clock at 5:00, 7:15, an 3:35?

Mathematics
1 answer:
sveticcg [70]4 years ago
8 0
A) 5:00 
<span>At 00 minutes, the minute hand is point straight up. That is one quarter turn of the entire circle. One-fourth of 2π radians is 1/2 π, or π/2 </span>

b) 7:15 
At 15 minutes, the minute hand is pointing straight to the right, along the imaginary positive x-axis, so it has turned through none of the circle. 0 radians.

c) 3:30 
<span>This one isn't as clean as the others. Let's first find the 35 minute position: it occurs at hour number 7. Identify that measuring from 3 (positive x-axis, measuring counter clockwise) you have to turn through 40 minutes worth of clock. 40 minutes represents 40/60 of an entire clock, which reduces to 2/3. 2/3 of all the radians in a circle (2π of them) is 4/3π, or 4π/3. 

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
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What is the y-intercept of the line perpendicular to the line y = 3/4x + 3 that includes the point (-3, -3)
kipiarov [429]
A perpendicular line has an opposite reciprocal slope. This means that the new line will have a slope of -4/3x. Plug in x and y into the equation y=Mx +b where m is the slope (-4/3):
-3=(-3/4)(-3) + b
and isolate b:
b-3=(-3/4)(-3)
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b=9/4+3
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The final equation is y= -4/3x + 21/4
The y intercept is (21/4).
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Find the length of arc AD. Use 3.14for r. Round to the nearest tenth.7.9 cmB66.4DС[? ]cmEntar
ch4aika [34]

The first thing we must do is calculate the circumeference:

\begin{gathered} c=2\cdot\pi\cdot r \\ c=2\cdot3.14\cdot7.9 \\ c=49.612 \end{gathered}

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360° - 66.4° - 180° = x

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now, to calculate the arc length it would be:

undefined

5 0
2 years ago
A tanget is ____ to the radius that shares the point of tengency
Mazyrski [523]
I believe it is C hope it helps
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4 years ago
HELPPPPP ASAPPPP
KATRIN_1 [288]

Answer:

The maximum height of the volleyball is 12.25 feet.

Step-by-step explanation:

The height of the volleyball, h(t), is modeled by this equation, where t represents the  time, in seconds, after that ball was set :

h(t)=-16t^2+20t+6 ....(1)

The volleyball reaches its maximum height after 0.625 seconds.

For maximum height,

Put \dfrac{dh}{dt}=0

Now put t = 0.625 in equation (1)

h(t)=-16(0.625)^2+20(0.625)+6\\\\h(t)=12.25\ \text{feet}

So, the maximum height of the volleyball is 12.25 feet.

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There are 4 semi-trailer trucks parked in a line at the rest stop. After the first truck, each truck in the line weighs 2 tons m
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5+7= 12 +9 = 21+11= 32.
6 0
3 years ago
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