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valentinak56 [21]
3 years ago
9

How can I find the angular position in radians of the minute hand of a clock at 5:00, 7:15, an 3:35?

Mathematics
1 answer:
sveticcg [70]3 years ago
8 0
A) 5:00 
<span>At 00 minutes, the minute hand is point straight up. That is one quarter turn of the entire circle. One-fourth of 2π radians is 1/2 π, or π/2 </span>

b) 7:15 
At 15 minutes, the minute hand is pointing straight to the right, along the imaginary positive x-axis, so it has turned through none of the circle. 0 radians.

c) 3:30 
<span>This one isn't as clean as the others. Let's first find the 35 minute position: it occurs at hour number 7. Identify that measuring from 3 (positive x-axis, measuring counter clockwise) you have to turn through 40 minutes worth of clock. 40 minutes represents 40/60 of an entire clock, which reduces to 2/3. 2/3 of all the radians in a circle (2π of them) is 4/3π, or 4π/3. 

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
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Answer:

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Step-by-step explanation:


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natta225 [31]

I don't know for sure but I think it is either b or c


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Jasmine cooked 1 5/6 kg of rice. Alice cooked 5/8 kg more than Jasmine. a. How many kg of rice did Alice cook? b. How many kg of
larisa86 [58]

Answer:Amount of rice cooked by Alice =2 11/24kg

Together  Alice and Jasmine cooked 4 7/24kg of rice

Step-by-step explanation:

Amount of rice cooked by Jasmine =1 5/6 kg

Amount of rice cooked by Alice = 5/8 kg more than Jasmine

=1 5/6 kg+ 5/8 kg

=1 (20 +15) /24

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6 0
3 years ago
C(0)= -.30(12-12)^2 + 40 (what it equals to
anygoal [31]
12-12 is 0, so -.30(12-12)^2 = 0

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3 0
3 years ago
I have two children. One is a boy born on a Tuesday. What is the probability that I have two boys?
valkas [14]
Let's handle this case by case.

Clearly, there's no way both children can be girls.  There are then two cases:

Case 1: Two boys.  In this case, we have 13 possibilities:  the first is born on a Tuesday and the second is not (that's 6 possibilities, six ways to choose the day for the second boy), the first is not born on a Tuesday and the second is (6 more possibilities, same logic), and both are born on a Tuesday (1 final possibility), for a total of 13 possibilities with this case.

Case 2: A boy and a girl.  In this case, there are 14 possibilities:  The first is a boy born on a Tuesday and the second is a girl born on any day (7 possibilities, again choosing the day of the week.  We are counting possibilities by days of the week, so we must be consistent here.), or the first is a girl born any day and the second is a boy born on a Tuesday (7 possibilities).

We're trying to find the probability of case 1 occurring given that case 1 or case 2 occurs.  As there's 13+14=27 ways for either case to occur, we have a 13/27 probability that case 1 is the one that occurred.
8 0
3 years ago
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