The answer to your question you see if two equals G0 in at four equals G2
Lets say that:
X = price of each notebook
Y = price of each newspaper
So from the problem statement we can create the following equations:
40 X + 20 Y = 130 --> eqtn 1
8 X + 4 Y = 28 --> eqtn 2
Divide both equations by the lowest coefficient to simplify:
Divide eqtn 1 by 20 => 2 X + Y = 6.5
Divide eqtn 2 by 4=> 2 X + Y = 7
So we can see that although both equations has equal left side, the right side do not match. Hence this problem is impossible to solve.
so the given information describes an impossible situation.
Answer:
7+3(-4)(2) -2[12/(-3)] (15-7)-(9/3) -5[7+(-14)]-30= 49
Step-by-step explanation:
Let "x" be the longest side and "y" be each of <span>remaining sides
If the triangle is </span>аcute<span> then:
</span>y² + y² > x² <span>
2y</span>² > 30²
2y² > 900
y² > 450
<span>y > </span>√450
y > 21.21 ← <span>to the nearest hundredth
</span>
This means the length of each of the remaining sides is not less than 21.22 in (to the nearest hundredth), so <span>the smallest possible perimeter of the triangle =
30 + 21.22 + 21.22 = 72.44 in.
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