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Natasha2012 [34]
3 years ago
7

What is the volume of 1.50 lb (pounds) of mercury? The density of mercury is 13.546 g/mL. Use the conversion that 1 kg = 2.20 lb

. mL.
Chemistry
1 answer:
Arada [10]3 years ago
7 0

Answer:

50.3mL of mercury are in 1.50lb

Explanation:

Punds are an unit of mass. To convert mass to volume we must use density (13.546g/mL). Now, As you can see, density is in grams but the mass of mercury is in pounds. That means we need first, to convert pounds to grams to use density and obtain volume of mercury.

<em>Mass mercury in grams:</em>

1.50lb * (1kg / 2.20lb) = 0.682kg = 682g of mercury.

<em>Volume of mercury:</em>

682g Mercury * (1mL / 13.546g) =

<h3>50.3mL of mercury are in 1.50lb</h3>
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Answer:

here's a great idea!

take a jug of water by finding the volume of that water and ask the 2 year old to chug it all in... the volume of water drank by the 2 year old is the volume of the two year old

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Explain how a water strider can float on the surface of water without sinking.
Rainbow [258]

Answer:

low weight and great area

Explanation:

8 0
3 years ago
Consider these changes.
Ede4ka [16]

Answer:

(a) The system does work on the surroundings.

(b) The surroundings do work on the system.

(c) The system does work on the surroundings.

(d) No work is done.

Explanation:

The work (W) done in a chemical reaction can be calculated using the following expression:

W = -R.T.Δn(g)

where,

R is the ideal gas constant

T is the absolute temperature

Δn(g) is the difference between the gaseous moles of products and the gaseous moles of reactants

R and T are always positive.

  • If Δn(g) > 0, W < 0, which means that the system does work on the surroundings.
  • If Δn(g) < 0, W > 0, which means that the surroundings do work on the system.
  • If Δn(g) = 0, W = 0, which means that no work is done.

<em>(a) Hg(l) ⇒ Hg(g)</em>

Δn(g) = 1 - 0 = 1. W < 0. The system does work on the surroundings.

<em>(b) 3 O₂(g) ⇒ 2 O₃(g) </em>

Δn(g) = 2 - 3 = -1. W > 0. The surroundings do work on the system.

<em>(c) CuSO₄.5H₂O(s) ⇒ CuSO₄(s) + 5H₅O(g) </em>

Δn(g) = 5 - 0 = 5. W < 0. The system does work on the surroundings.

<em>(d) H₂(g) + F₂(g) ⇒ 2 HF(g)</em>

Δn(g) = 2 - 2 = 0. W = 0. No work is done.

3 0
3 years ago
Carbon dioxide is made up of carbon and oxygen atoms is it an element or a compound
Ratling [72]

Carbon Dioxide is a compound gas

Carbon Dioxide is a gas produced by burning carbon and organic compounds and by respiration.

6 0
3 years ago
Read 2 more answers
24. A sports ball is inflated to an internal pressure of 1.85 atm at room temperature (25 °C). If the ball is then played with o
baherus [9]

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant volume.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}        (at constant volume)

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

Conversion factor:  T(K)=T(^oC)+273

P_1=1.85atm\\T_1=25^oC=(25+273)K=298K\\P_2=?atm\\T_2=7.5^oC=(7.5+273)K=280.5

Putting values in above equation, we get:

\frac{1.85atm}{298K}=\frac{P_2}{280.5K}\\\\P_2=1.74atm

Hence, the correct answer is Option B.

6 0
2 years ago
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