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kari74 [83]
3 years ago
15

Determine the [h3o+] of a 0.210 m solution of formic acid.

Chemistry
1 answer:
Nataly [62]3 years ago
3 0
When the Pka for formic acid = 3.77
and Pka = -㏒ Ka 
   3.77 = -㏒ Ka
∴Ka = 1.7x10^-4 

when Ka = [H+][HCOO-}/[HCOOH]

when we have Ka = 1.7x10^-4 &[HCOOH] = 0.21 m
so by substitution: by using ICE table value
1.7x10^-4 = X*X / (0.21-X)
(1.7x10^-4)*(0.21-X) = X^2      by solving this equation for X

∴X = 0.0059
∴[H+] = 0.0059
∴PH= -㏒ [H+]
       = -㏒ 0.0059
       = 2.23 

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Conservation of mass was discussed in the background. Describe how conservation of mass (actual, not theoretical) could be check
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3 0
3 years ago
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8 0
2 years ago
If 3.45 grams of Mg are burned how many grams of MgO are produced
coldgirl [10]
  The  number   of grams  of Mgo   that  are  produced  is calculated  as follows
  calculate  the  moles  of  Mg  used

that  is  moles =mass/molar  mass
=  3.45  g/  24.305g/mol  = 0.142  moles

write  the  equation  for  reaction
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4 0
2 years ago
Read 2 more answers
Two reactions and their equilibrium constants are given. A + 2 B − ⇀ ↽ − 2 C K 1 = 2.79 2 C − ⇀ ↽ − D K 2 = 0.186 Calculate the
vfiekz [6]

Answer:

K=1.93

Explanation:

Given reactions are:

A +2B ⇄ 2C  K1=2.79

2C ⇄ D K2=0.186

D⇄ A+ 2B K=?

If we reverse the reaction then the euillibrium constant also become reciprocal of original value:

3rd reaction is a combination of reciprocal of 1st and 2nd reaction

2C⇄A +2B   1/K1;........................1

D ⇄ 2C  1/K2; ..............................2

On adding 1 and 2

D ⇄A +2B    K=\frac{1}{K1} \times\frac{1}{K2};

K=\frac{1}{2.79} \times\frac{1}{0.186};

K=1.93

4 0
3 years ago
Match the words to the appropriate blanks in the sentences.
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7 0
3 years ago
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