What is the value of x when the Richter scale rating is 7.9 round your answer to the nearest

1 answer:

4 0

If no base is stated, then assume base 10
$log(x)=log_{10}(x)$
rememer
$a=log_b(c)$ translates to $b^a=c$

so
$r=log(x)$ or
$r=log_{10}(x)$ translates to $10^r=x$

so when r=7.9, what is x
$10^r=x$
$10^{7.9}=x$
79432823.472428=x
round to nearest ???
thousanth? 79432823.472=x
hundreth? 79432823.47=x
tenth? 79432823.5=x

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

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Central Limit Theorem

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