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3 years ago

What is the value of x when the Richter scale rating is 7.9 round your answer to the nearest

1 answer:

4 0

If no base is stated, then assume base 10
$log(x)=log_{10}(x)$
rememer
$a=log_b(c)$ translates to $b^a=c$

so
$r=log(x)$ or
$r=log_{10}(x)$ translates to $10^r=x$

so when r=7.9, what is x
$10^r=x$
$10^{7.9}=x$
79432823.472428=x
round to nearest ???
thousanth? 79432823.472=x
hundreth? 79432823.47=x
tenth? 79432823.5=x

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54. Write the ratio as a fraction in simplest<br>form.<br>56 to 16

pshichka [43]

Answer:

56/16 = 3.5

Step-by-step explanation:

4 0

3 years ago

Help plz

Natalka [10]

Answer:

(4, 3)

Step-by-step explanation:

Since, A (-4, 3) is reflected across the y-axis to obtain point B.

Therefore, y coordinate remains the same, x coordinate flips over the y axis to be positive.

(-4,3) ==>> (4,3)

6 0

2 years ago

Assume that females have pulse rates that are normally distributed with a mean of u = 75.0 beats per minute and a standard devia

Elan Coil [88]

Answer:

36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 75, \sigma = 12.5$

Find the probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

This is the pvalue of Z when X = 81 subtracted by the pvalue of Z when X = 69.

X = 81

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{81 - 75}{12.5}$

$Z = 0.48$

$Z = 0.48$ has a pvalue of 0.6844

X = 69

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{69 - 75}{12.5}$

$Z = -0.48$

$Z = -0.48$ has a pvalue of 0.3156

0.6844 - 0.3156 = 0.3688

36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

3 0

3 years ago

Read 2 more answers

Please help if you can thanks ^^

Neko [114]

Given:

AD is an angle bisector in triangle ABC. $m\angle CAB=44^\circ, m\angle ACB=72^\circ, m\angle ABC=64^\circ$ .

To find:

The value of $m\angle ADC$ .

Solution:

AD is an angle bisector in triangle ABC.

$m\angle CAD=m\angle BAD=\dfrac{m\angle CAB}{2}$

$m\angle CAD=m\angle BAD=\dfrac{44^\circ}{2}$

$m\angle CAD=m\angle BAD=22^\circ$

According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees.

Using angle sum property in triangle CAD, we get

$m\angle CAD+m\angle ADC+m\angle ACB=180^\circ$

$22^\circ+m\angle ADC+72^\circ=180^\circ$

$m\angle ADC+94^\circ=180^\circ$

$m\angle ADC=180^\circ-94^\circ$

$m\angle ADC=86^\circ$

Therefore, the angle of angle ADC is $86^\circ$ .

3 0

3 years ago

A plane flies at a steady rate of 40 mph while a second plane flies at a steady rate of 100 mph. The planes are 200 miles apart

malfutka [58]

Answer:

The time the two planes will meet is 1.43 hours

Step-by-step explanation:

Given;

speed of the first plane in positive direction, = 40 mph

speed of the second plane in negative direction(opposite direction) = -100 mph

distance between the two planes = 200 miles

Let the time the two planes will meet = t

the position of the first plane at this time "t" = 40t

the position of the second plane at this time "t" = -100t

(40t)>--------------------------------<(-100t), this space between them is 200 miles.

Thus, the difference in the distance they traveled before meeting should be equal to 200 miles.

40t - (-100t) = 200

40t + 100t = 200

140t = 200

t = 200 / 140

t = 1.43 hours

Therefore, the time the two planes will meet is 1.43 hours

6 0

3 years ago