Question

A reaction is shown below. Reaction : 2 upper H subscript 2 upper O subscript 2 (l) right arrow with upper M n upper O subscript 2 (s) above it, 2 upper H subscript 2 upper O (l) plus upper O subscript 2 (g). What can be concluded about this reaction?
A homogeneous catalyst is being used in the reaction.
A heterogeneous catalyst is being used in the reaction.
A catalyst is not being used in this reaction.
An enzyme is being used in this reaction.

Answer 1

Answer:

heterogeneous catalyst

Explanation:

The reaction equation:

                        MnO₂$_{s}$

         H₂O₂$_{l}$         →             2H₂$_{g}$     +   2O₂$_{g}$

A catalyst is any species that speeds up the rate of chemical reactions. It does not get used up in the reaction but helps facilitate the rate by which two species combines.

In this reaction, MnO₂ is the catalyst used in this reaction.

The catalyst still remains at the end of the reaction.

  Now, we know that from the subscript, the reactant is in liquid phase, the products are in gaseous phase and the catalyst is in solid phase.

A catalyst in a reaction in a different phase with the reactants is called a heterogeneous catalyst.

Answer 2

Answer:

The answer is B. A heterogeneous catalyst is being used in the reaction.

Explanation: