The statement that correctly describes the reaction is: Tungsten (W) changes oxidation numbers from +6 to zero, so it undergoes reduction.
<h3>WHAT IS
OXIDATION AND REDUCTION:</h3>
- Oxidation is the process whereby electrons are lost in a reaction while reduction involves the gain of electrons.
- According to this question, the following reaction is given: WO3(s) + 3H2(g) → W(s) + 3H2O(g)
- Tungsten has an oxidation number of +6 in WO3 and it is changed to 0 in W, hence, there is a gain of electrons by tungsten (W).
Therefore, the statement that correctly describes the reaction is: Tungsten (W) changes oxidation numbers from +6 to zero, so it undergoes reduction.
Learn more about oxidation-reduction reaction at: brainly.com/question/3867774
<h3>
Answer:</h3>
266.325 g
<h3>
Explanation:</h3>
We are given the balanced equation;
2NaOH + H₂SO₄ → H₂O + Na₂SO₄
We are required to determine the mass of Na₂SO₄ that will be formed.
<h3>Step 1: Determine the number of moles of NaOH</h3>
Moles = Mass ÷ molar mass
Molar mass of NaOH is 40.0 g/mol
Therefore;
Moles of NaOH = 150 g ÷ 40 g/mol
= 3.75 moles
<h3>Step 2: Determine the number of moles of sodium sulfate formed</h3>
- From the equation 2 moles of NaOH reacts with sulfuric acid to form 1 mole of sodium sulfate.
- Therefore; mole ratio of NaOH : Na₂SO₄ is 2 : 1
Thus, moles of Na₂SO₄ = Moles of NaOH ÷ 2
= 3.75 moles ÷ 2
= 1.875 moles
<h3>Step 3: Determine the mass of Na₂SO₄ produced.</h3>
we know that;
Mass = Moles × Molar mass
Molar mass of Na₂SO₄ is 142.04 g/mol
Therefore;
Mass of Na₂SO₄ = 1.875 moles × 142.04 g/mol
= 266.325 g
Thus, the mass of sodium sulfate formed 266.325 g
1. <span>C. accept an electron pair
2. </span><span>E. solid, liquid, and gas
</span>
Balanced equation : 2Na+I₂⇒2NaI
<h3>Further explanation
</h3>
Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:
• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.
• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product
• 3. Select the coefficient of the substance with the most complex chemical formula equal to 1
Reaction
Na+I₂⇒NaI
aNa+bI₂⇒NaI
Na, left=a, right=1⇒a=1
I, left=2b, right=1⇒2b=1⇒b=0.5
Equation becomes :
Na+0.5I₂⇒NaI x 2
2Na+I₂⇒2NaI
