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telo118 [61]
3 years ago
14

Why is it necessary to find the percent yield of a reaction

Chemistry
2 answers:
Leokris [45]3 years ago
5 0
The yield of a reaction is the final product. It is necessary to find the percent yield of a reaction since the efficiency of the reaction can be determined.

Mariulka [41]3 years ago
4 0

<u>Explanation:</u>

Percent yield is defined as the percent ratio of experimental yield by the theoretical yield. The equation used to calculate this quantity is given by:

\text{Percent yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

This is necessary because during a reaction, many by-products are formed along with the required product. So, to judge the product we require this. This is very important in the synthesis of the product. This is also used to detect if there is any impurity in the product or not.

Like, if the percent yield is more than 100%, it means that the product carry some impurity in it and it has to be removed. This is also used to know that if all the reactants have reacted together or not.

Hence, knowing percent yield helps in many ways.

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HELPPPP ASAP!!! Plzzz
Ad libitum [116K]

Answer:

420 miles

Explanation:

From the question given above, the following data were obtained:

Time = 3.5 hours

Speed = 120 mi/h

Distance =?

Speed is defined as the distance travelled per unit time. Mathematically, it is expressed as:

Speed = distance / time

With the above formula, we can obtain the distance travelled by the plane as follow:

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How would oxygen be represented in the formula equation for the reaction of methane and oxygen to yield carbon dioxide and water
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Answer:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Explanation:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Methane + oxygen → carbon dioxide + Water.

The balanced equation above shows the combustion of methane, CH4 in oxygen, O2 to yield carbon dioxide, CO2 and steam, H2O.

The mole ratio of combustion are as follows:

1 mole of CH4 burns in 2 moles of oxygen to produce 1 mole of CO2 and 2 moles of H2O and a lot of heat.

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