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IceJOKER [234]
3 years ago
6

Which of the following is an example of a rational number?

Mathematics
1 answer:
viva [34]3 years ago
5 0
B) 3.456733244.. because that number keeps going on and is repeated
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PLEASE HELP ME!¡!¡!¡ :)))
jonny [76]
I think the answer is c because there is no pattern and linear has to have a pattern so nonlinear doesn't have a pattern. Thats why the answer is c.
7 0
3 years ago
What is the lower quartile of the data? 16, 18, 59, 75, 30, 34, 25, 49, 27, 16, 21, 58, 71, 19, 50
svetlana [45]

Answer:

19.

Step-by-step explanation:

First arrange in ascending order:

16, 16, 18, 19, 21, 25, 27, 30, 34, 49, 50, 58, 59, 71, 75.

There are a total of 15 numbers, so the median is the 8th number = 30.

The lower quartile is halfway alone the first 7 numbers which is the 4th number and it is 19.

The median which is the middle number

4 0
3 years ago
The cube root is the same as______
Ksju [112]

Answer:

the third root

Step-by-step explanation:

4 0
2 years ago
The Cowboys High School Band Boosters are selling candy bars and chips at the basketball tournament to raise money for their ban
masya89 [10]

Answer:

They have 425 candy bars ready to sell.

Step-by-step explanation:

Let,

x be the number of candy bars ready to sell

y be the number of chips ready to sell

According to given statement;

x+y=575     Eqn 1

x+0.5y= 500     Eqn 2

Subtracting Eqn 2 from Eqn 1

(x+y)-(x+0.5y)=575-500

x+y-x-0.5y=75

0.5y = 75

Dividing both sides by 0.5

\frac{0.5y}{0.5}=\frac{75}{0.5}\\y=150

Putting y=150 in Eqn 1

x+150 = 575

x = 575-150

x = 425

Hence,

They have 425 candy bars ready to sell.

7 0
3 years ago
Parts being manufactured at a plant are supposed to weigh 65 grams. Suppose the distribution of weights has a Normal distributio
andrew-mc [135]

Answer:

0.64%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 75 grams and a standard deviation of 22 grams.

This means that \mu = 75, \sigma = 22

Sample of 144:

This means that n = 144, s = \frac{22}{\sqrt{144}} = 1.8333

More than 80 or less than 70:

Both are the same distance from the mean, so we find one probability and multiply by 2.

The probability that it is less than 70 is the pvalue of Z when X = 70. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{70 - 75}{1.8333}

Z = -2.73

Z = -2.73 has a pvalue of 0.0032

2*0.0032 = 0.0064.

0.0064*100% = 0.64%

The probability is 0.64%.

3 0
3 years ago
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