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Rzqust [24]
3 years ago
13

He henry's law constant of oxygen in water at 25 °c is 773 atm mol-1kg h2o. calculate the molality of oxygen in water under a p

artial pressure of 0.20 at
Chemistry
1 answer:
motikmotik3 years ago
4 0
Henry law:

P = KC
P = solvent vapour pressure
K = Henry constant 
C = conc of solute

So,   0.2 = 773 C
so, C =  0.2 / 773 =   2.5 x 10^{-4} molal
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