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4 years ago

HELPPP MEE I NEED HELPP PLEASE

Chemistry

1 answer:

VARVARA [1.3K]4 years ago

7 0

Answer:

B.Michanine

Explanation:

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What is the [oh−] of a solution with ph 5.75

Gekata [30.6K]

[ H₃O⁺] = 10 ^- pH

[ H₃O⁺] = 10 ^ (- 5.75 )

[H₃O⁺] = 1.778x10⁻⁶ M

Kw = [ H₃O⁺] x [ OH⁻]

1x10⁻¹⁴ = 1.778x10⁻⁶ x [OH⁻]

[OH⁻] = 1x10⁻¹⁴ / 1.778x10⁻⁶

[OH⁻] = 5.62x10⁻⁹ M

hope this helps!

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3 years ago

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Alexandra [31]

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3 years ago

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Write one question you have about Duke Ellington and Billy Strayhorn

coldgirl [10]

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Duke Ellington's (1941) number 1 hit song, he wrote with Billy Strayhorn was 'Take the A train'.

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3 years ago

Which of the following reactions is balanced?

Vsevolod [243]

The answer is A
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3 years ago

A chemist must prepare 800.0mL of sodium hydroxide solution with a pH of 12.10 at 25°C. She will do this in three steps: Fill a

AnnZ [28]

Answer:

0.42 g

Explanation:

pH = 12.10 (25 °C)

V = 800.0 mL = 0.800 L

To find the mass of sodium hydroxide (NaOH) we can use the pH:

$14 = pH + pOH$

$pOH = 14 - pH = 14 - 12.10 = 1.90$

$pOH = -log ([OH^{-}])$

$[OH]^{-} = 10^{-pOH} = 10^{-1.90} = 0.013 M$

Now, we can find the number of moles (η) of OH:

$\eta = ([OH]^{-})*V = 0.013 mol/L * 0.800 L = 1.04 \cdot 10^{-2} moles$

Since we have 1 mol of OH in 1 mol of NaOH, the number of moles of NaOH is equal to 1.04x10⁻² moles.

Finally, with the number of moles we can find the mass of NaOH:

$m = \eta * M$

<em>Where M is the molar mass of NaOH = 39.9 g/mol </em>

$m = 1.04 \cdot 10^{-2} moles * 39.9 g/mol = 0.42 g$

Therefore, the mass of sodium hydroxide that the chemist must weigh out in the second step is 0.42 g.

I hope it helps you!

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3 years ago