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shtirl [24]
2 years ago
6

Which element rarely reacts because it has 8 electrons in its outer shell?

Chemistry
2 answers:
mojhsa [17]2 years ago
8 0

Answer:

C. Arsenic

Explanation:

Each period is terminated by a noble gas with a closed valence shell with electronic configuration ns²np⁶. Since noble gases have completely filled orbitals in the valence shell and are very stable, it becomes very difficult to alter their stable arrangement by the addition or removal of electrons. They they exhibit very low chemical reactivity.

Noble gas elements are: Neon, Argon, Krypton, Xenon, Radon, Helium (2 electrons in outer shell, stable).

timama [110]2 years ago
7 0

Answer:

B. Xenon

Explanation:

A.P.E.X

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vovangra [49]

Answer:

B. the products have a smaller number of available energy microstates than the reactants.

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2 years ago
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What is the energy of a photon of red light that has a frequency of 4.48 X 10^14Hz?
lana [24]

Answer:

E = 29.7× 10⁻²⁰  j

Explanation:

Given data;

Frequency of light = 4.48 × 10¹⁴ Hz

Energy of photon = ?

Solution:

Formula:

E = h.f

E = energy of photon

h = planck's constant

f = frequency

E = h.f

E = 6.63 × 10⁻³⁴ Kg.m² /s × 4.48 × 10¹⁴ s⁻¹

E = 29.7× 10⁻²⁰ Kg.m²/s²

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3 0
2 years ago
Which of the following describes metallic character on the periodic table? Question 1 options: A) It increases as you move right
Ilia_Sergeevich [38]

Answer:

D

Explanation:

Metallic character decreases as you move across a period in the periodic table from left to right. This occurs as atoms more readily accept electrons to fill a valence shell than lose them to remove the unfilled shell. Metallic character increases as you move down an element group in the periodic table. This is because electrons become easier to lose as the atomic radius increases, where there is less attraction between the nucleus and the valence electrons because of the increased distance between them.

3 0
2 years ago
Which of the following is a correct inference that one can make about the burning of gasoline?
VLD [36.1K]

Answer:

It’s a physical change

Explanation:

4 0
3 years ago
The rate constant for this second‑order reaction is 0.610 M − 1 ⋅ s − 1 0.610 M−1⋅s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶product
Darya [45]

Answer: It takes 3.120 seconds for the concentration of  A to decrease from 0.860 M to 0.260 M.

Explanation:

Integrated rate law for second order kinetics is given by:

\frac{1}{a}=kt+\frac{1}{a_0}

k = rate constant = 0.610M^{-1}s^{-1}

a_0 = initial concentration = 0.860 M

a= concentration left after time t = 0.260 M

\frac{1}{0.260}=0.860\times t+\frac{1}{0.860}

t=3.120s

Thus it takes 3.120 seconds for the concentration of  A to decrease from 0.860 M to 0.260 M.

8 0
3 years ago
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