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shtirl [24]
3 years ago
6

Which element rarely reacts because it has 8 electrons in its outer shell?

Chemistry
2 answers:
mojhsa [17]3 years ago
8 0

Answer:

C. Arsenic

Explanation:

Each period is terminated by a noble gas with a closed valence shell with electronic configuration ns²np⁶. Since noble gases have completely filled orbitals in the valence shell and are very stable, it becomes very difficult to alter their stable arrangement by the addition or removal of electrons. They they exhibit very low chemical reactivity.

Noble gas elements are: Neon, Argon, Krypton, Xenon, Radon, Helium (2 electrons in outer shell, stable).

timama [110]3 years ago
7 0

Answer:

B. Xenon

Explanation:

A.P.E.X

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The angle of incoming sunlight varies at different places.

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What is the molar mass for a solute if 32.38 g of the solute dissolved in 296 g of water
Pie

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this is math

Explanation:

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Which of these are isotopes of each other? Boron-12, Carbon-12, Carbon-13, Nitrogen-13
Anika [276]
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5 0
4 years ago
Choose the products that complete the reaction NaHCO3+HC2H3O2
Novosadov [1.4K]

Answer:

The products will be;

CO₂ + H₂O + NaC₂H₃O₂

Explanation:

We are given;

Two reactants NaHCO₃ and HC₂H₃O₂

We are supposed to determine the products;

  • We need to know that hydrogen carbonates reacts with acids to give water, carbon dioxide and a salt as the products.

Therefore;

  • In this case, sodium hydrogen carbonates (baking soda) reacts with acetic acid to form water, carbon dioxide and sodium acetate.
  • The equation for the reaction is;

      NaHCO₃ + HC₂H₃O₂ → CO₂ + H₂O + NaC₂H₃O₂

  • Therefore, the products of the complete reaction between sodium hydrogen carbonate and acetic acid are CO₂ + H₂O + NaC₂H₃O₂
3 0
3 years ago
It is desired to make 1.00 liter of 6.00 M nitric acid from concentrated 16.00 M HNO3.A) How many moles of nitric acid are in 1.
natima [27]

Answer:

A) 6.00 mol.

B) 0.375 L or 375 mL

C) 6.00 M

Explanation:

Hello,

A) In this case, from the definition of molarity, we compute the moles for the given volume and concentration:

n=M*V=1.00L*6.00mol/L=6.00mol

B) In this case, from the stock solution, the required volume is:

V=\frac{6.00mol}{16.00mol/L}=0.375L

C) In this case, we apply the following formula for dilution process:

M_1V_1=M_2V_2

Thus, solving for the final molarity, we obtain:

M_2=\frac{M_1V_1}{V_2}=\frac{16.00M*0.375L}{1.00L}\\  \\M_2=6.00M

Regards.

5 0
3 years ago
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