Answer:
0%
Explanation:
Achondroplasia is an autosomal dominant disorder that is expressed in both homozygous and heterozygous dominant genotypes. Since two affected parents have a normal girl child, both the parents should be heterozygous carrier for the disease. Let's assume that the dominant allele "A" is responsible for the disease. Genotype of both the parents of the girl would be "Aa". The genotype of girl with normal stature is "aa". Genotype of her normal partner is "aa".
A cross betwee aa X aa would get all the progeny with "aa" genotype. Therefore, all of their children would have normal stature and there is 0% probability for them to have a child with achondroplasia.
A)
Therefore:Crossing results in 50% (dominant homozygote) and 50% (dominant heterozygote).
b)
Therefore:Crossing results in 25% (dominant homozygote), 50% (dominant heterozygote) and 25% (homozygous recessive).
c)
Therefore:Crossing results in 100% (homozygous recessive).
Answer:
All the choices are correct
Answer: The correct answer to the question is option C
OSTEOARTHRITIS.
The client has a degenerative form of disease that is evidenced by osteoarthritis.
Explanation: Osteoporosis is otherwise known as degenerative joint disease.
In a healthy joint,a protective cartilage cushions the end of bones(articulating bones) and as well acting as a shock absorber.
In osteoarthritis,these cartilage that acts as a cushion to the bones wears down down or generates with time exposing the joint and the bones predisposing them to mild to moderate friction that occurs as a result of mobility of the bones/joint.
Osteoarthritis mostly affect joints of the hips, hands,spine and knees.
Some of the common symptoms of Osteoarthritis are;pain in the joints of the hands,knees,hips,lower back and neck with crackles,stiffness and tenderness of the joints which often results to difficulty in walking and deformity of the joint if left untreated.
