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ratelena [41]
3 years ago
5

Which of these is one way that mechanical waves differ from electromagnetic waves?

Physics
2 answers:
Andrew [12]3 years ago
6 0
<span>Mechanical waves require a medium
and electromagnetic waves do not.</span>
Licemer1 [7]3 years ago
6 0

<u>Answer:</u> The correct statement is mechanical waves require a medium and electromagnetic waves do not.

<u>Explanation:</u>

Electromagnetic waves and mechanical waves differ in the way of propagation.

Electromagnetic waves are the waves which does not require a medium to  travel through. These waves can travel through vacuum. These waves have electrical and magnetic component associated with them. Light waves are a type of electromagnetic waves.

Mechanical waves are the waves that require a medium to travel through. They transport energy from one location to the other with the help of particles present in the medium. These waves travel faster in solids because the particles lie closer to each other. Sound waves are a type of mechanical waves.

Hence, the correct statement is mechanical waves require a medium and electromagnetic waves do not.

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3 years ago
A uniform horizontal beam of weight 481 N and length 3.32 m has two weights hanging from it. One weight of 381 N is located 0.87
Andre45 [30]

Answer:

1143 N at 1.59 m from the left end

Explanation:

For the system to produce equilibrium, the total force and moment must be 0. Since the total weight downward is

481 + 381 + 281 = 1143 N

Therefore the magnitude of the force acting upward to balance this system must be the same of 1143 N

That alone is not enough, we also need the position of the force for the total moment to be 0.

Let x be the length from the this upward force to the left side. And let the left point be the point of reference for moment arm:

481 * 3.32/2 + 381 * 0.8798 + 281*(3.32 - 0.8798) - 1143*x = 0

x = (481*1.66 + 381 * 0.8798 + 281*2.4402)/1143 = 1.59m

5 0
4 years ago
An object weighing 4 newtons swings on the end of a string as a simple pendulum. At the bottom of the swing, the tension in the
Anit [1.1K]

Answer:

(B) 0.5 g

Explanation:

Newton's second law says ∑  F i = m a .

the rate of change in momentum of a body is proportional to the force applied on the body.

f∝ma

f=kma

were k is constant and equal to 1

The centripetal acceleration is an acceleration.

the tension on the swing and object weight goes to the left hand side while the centripetal acceleration goes to the right handside

At the bottom of the swing, ΣF = FT – mg = mac;

notice that the tension in the swing is 1.5 times the weight of the object

we can write

1.5mg – mg = mac,

0.5mg = mac

0.5 g=ac

8 0
3 years ago
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