A retail gasoline pump is able to fill a 14.0 gallon automobile tank in 1.50 minutes. What is the mass flow rate deliverd by the

Question

4 years ago

9

gasoline pump in lbm/min

2 answers:

Ludmilka [50] · Answer 1 · 2022-01-24T07:03:10+03:00

We have volume of gasoline = 14.0 gallon

Time taken to fill automobile tank = 1.50 minutes

So volume rate = 14.0 gallon/1.50 minutes = 9.33 gallon/ minute

We have density of gasoline = 0.77 kg/L = 6.073 lb/US gal

Mass rate = Density * Volume rate

= 9.33 gallon/ minute*6.073 lb/US gal = 56.68 lb/min

So mass flow rate delivered by the gasoline pump in lbm/min = 56.68

kodGreya [7K] · Answer 2 · 2022-01-24T09:03:25+03:00

Answer:

58.3 lbm/min

Explanation:

The density of gasoline is 6.25 lbm/gal. The mass corresponding to 14.0 gallons of gasoline is:

14.0 gal × (6.25 lbm/gal) = 87.5 lbm

87.5 pound-mass of gasoline are delivered by the pump for 1.50 minutes. The mass flow rate is:

87.5 lbm/1.50 min = 58.3 lbm/min

The mass flow rate is 58.3 lbm/min.