Question

Probability theory predicts that there is a 56.6% chance of a particular basketball player making 5 free throws in a row. If the basketball player taking 5 free throws is simulated 5000 times, in about how many of the simulations would you expect at least 1 missed free throw?

Answer 1

Answer with explanation:

It is given that ,According to Probability theory  there is a 56.6% chance of a particular basketball player making 5 free throws in a row.

If, Number of throws=5,000

So, number of throws in which basketball player will make 5 free throws

    =56.6 % of 5,000

   $=\frac{56.6}{100}\times 5000=2830$

Number of Simulation , in which the basketball player can have at least 1 missed free throw

 = 5000-2830

=2170

Answer 2

the answer is 2170 that is the answer for apex