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3 years ago

Jazzmin has 2/5 of a pie. How many 1/10's of a whole pie are there in 2/5 of a whole pie?

Mathematics

1 answer:

Svetllana [295]3 years ago

8 0

Answer:

4/10

Step-by-step explanation:

when converting fractions, you multiply the numerator and the denominator by the same number. In this case, multiply it by 2, giving you 4/10.

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Factor the polynomial: 3x^2 - 9x - 30

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NICKI IS THE QUEEN OF RAPPP

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3 years ago

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Determine the smallest integer that makes – 3.2 + 7 - 52 < 15 true.

Natalija [7]

Answer:

-3.2 is the smallest integer

Step-by-step explanation:

3 0

3 years ago

The store paid $2. 70 for a book and sold it for $6. 20. What is the profit as a percent?.

bogdanovich [222]

Answer:

profit = 129.63% (to the nearest hundredth) as a percent of the price the store paid for the book

Step-by-step explanation:

Use the percentage change formula:

percent change = [ (difference between the initial value and the final value) ÷ initial value] x 100

= [ (6.20 - 2.70) ÷ 2.70 ] x 100

= [ 3.5 ÷ 2.70 ] x 100

= 37/27 x 100

= 129.6296296...

= 129.63% (to the nearest hundredth)

5 0

2 years ago

A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we

weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weighing of specimen = $\frac{3.412+3.416+3.414}{3}$ = 3.414 g

$\sigma$ = population standard deviation = 0.001 g

n = sample of specimen = 3

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } }$ , $3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } }$ ]