The answer is C.
You want:
10 < a < 14 (greater or equal)
The difference between 10 and 12 is 2.
The difference between 12 and 14 is 2.
Therefore the absolute value allows you to express that the difference between a and 12 cannot be greater than 2 (either going up to a max of 14 or going down to a minimum of 10).
<span>Step 1:
</span>
<span> (((22•5x2) + 25x) - 12x) - 15)))
</span>
<span>The first term is, <span> <span>20x2</span> </span> its coefficient is <span> 20 </span>.
The middle term is, <span> +13x </span> its coefficient is <span> 13 </span>.
The last term, "the constant", is <span> -15
</span></span>
<span>step 2 above, -12 and 25
<span>20x2 - 12x</span> + 25x - 15
Step-4 : Add up the first 2 terms, pulling out like factors :
4x • (5x-3)
Add up the last 2 terms, pulling out common factors :
5 • (5x-3)
Step-5 : Add up the four terms of step 4 :
(4x+5) • (5x-3)
Which is the desired factorization</span>Final result :<span> (5x - 3) • (4x + 5)
</span>
How many times were they swung? 0.0 .....
if swung twice.. I think the answer would be 27.16
.
Answer:
ABC = DEF by the SAS Postulate
