Ask question

Ask question

All categories

3 years ago

5

The speed of sound is 330.0 m/s and the wave length of a particular sound wave is 33.0 meters. Calculate the frequency of the so

und wave.
A)11,000 Hz B)10.0 Hz C) 0.10 Hz D)9.1 x 10-5 Hz

2 answers:

Alekssandra [29.7K]3 years ago

6 0

V: velocity of wave
f: frequency
L: wavelenght

<span>v = fL => f = v/L => f = (330)/(33) => L = 10Hz</span>

Nataly [62]3 years ago

6 0

Answer:

B). f = 10.0 Hz

Explanation:

As we know the relation between frequency, wavelength and speed is given as

$v = f \lambda$

here we know that

$v = 330 m/s$

$\lambda = 33 m$

now in order to find the frequency of the sound we can use above relation as

$f = \frac{v}{\lambda}$

plug in all values in it

$f = \frac{330}{33}$

$f = 10 Hz$

You might be interested in

An empty parallel plate capacitor is connected between the terminals of a 4.4-V battery and charged up. The capacitor is then di

torisob [31]

Answer:

d

Explanation:

idk

7 0

3 years ago

A circuit containing an inductor and a capacitor in series is designed to have a resonant frequency of 4511 Hz. If the inductor

OLEGan [10]

Answer:

(e) $6.835\times 10^{-7}F$

Explanation:

At resonance we know that $X_l=X_C$

That is $\omega L=\frac{1}{\omega C}$

$\omega ^2=\frac{1}{LC}$

$\omega =\frac{1}{\sqrt{LC}}$

$f=\frac{1}{2\pi \sqrt{LC}}$

We have given resonance frequency f =4511 Hz and inductance L=1.82 mH

So $4511=\frac{1}{2\pi \sqrt{LC}}$

$LC=\frac{1}{4\pi ^2\times 4511^2}$

$LC=1.244\times 10^{-9}$

$C=\frac{1.244\times 10^{-9}}{1.82\times 10^{-3}}=0.6835\times 10^{-6}=6.835\times 10^{-7}F$

So option e is the correct answer

3 0

3 years ago

Which one of the following substances is a liquid fuel used in rocket engines?

viva [34]

The substance which is a liquid fuel used in rocket engines is liquid oxygen. The correct answer is A.

5 0

2 years ago

You decide to clean the bathroom. You notice that the shower is covered in a strange green slime. You decide to try to get rid o

topjm [15]

The lemonade juice and water.

6 0

2 years ago

The head of a grass string trimmer has 100 g of cord wound in a light, cylindrical spool with inside diameter 3.00 cm and outsid

Karolina [17]

Answer:

a).11.546J

b).2.957kW

Explanation:

Using Inertia and tangential velocity

a).

$w=2250*2\pi *\frac{1}{60}\\ w=235.61$

$I=\frac{1}{2}*m*((\frac{d_{i} }{2})^{2} +(\frac{d_{e} }{2})^{2})\\m=100g *\frac{ikg}{1000g}=0.1kg\\ d_{i}=3cm*\frac{1m}{100cm}=0.03m \\ d_{e}=18cm*\frac{1m}{100cm}=0.18m\\I=\frac{1}{2}*0.1kg*((\frac{0.03m}{2})^{2} +(\frac{0.18m}{2})^{2})\\I=0.41625x10^{-3}kg*m^{2}$

Now using Inertia an w

$E=\frac{1}{2}*I*(w)^{2} \\ E=\frac{1}{2}*0.416x10^{-3}*(235.61)^{2} \\E=11.54J$

average power= $\frac{11.4J}{0.230s}=50.2 W$

b).

power=t*w

P= $11.5465*0.25*235.61$

P=2.957 kW

8 0

2 years ago

Read 2 more answers