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Sauron [17]
3 years ago
7

Please help with a step by step method ​

Physics
1 answer:
Elan Coil [88]3 years ago
3 0

Answer:

Explanation:

This is a First Law of thermodynamics problem. We have to remember that the total energy available to a system is constant throughout the whole problem and that energy cannot be created or destroyed. So we need to find the total energy available right at the start. Well it just so happens that we are told that the total energy is 1000J and that it is all potential energy when the sphere is at rest and is 25 m off the ground. If the object isn't moving, all the energy is potential until it starts moving and the energy begins to convert from potential to kinetic a little bit at a time. The thing that we don't know is the mass of the shpere. Begin with the fact that the PE = 1000 (I'm going to se 2 sig fig's since there's only 1 in 1000). If

PE = 1000 and PE = mgh, then

1000 = m(9.8)(25) so

m = 4.1 kg

We also need the height at which this sphere has a PE of 600. Again, if

PE = 600 and PE = mgh, then

600 = (4.1)(9.8)h so

h = 15 Filling in the total energy equation now, using the fact that the total energy available to the system is 1000J:

TE = PE + KE and

1000 = (4.1)(9.8)(15) + \frac{1}{2}(4.1)v^2 and we are looking for v.

1000 = 6.0 × 10² + 2.1v² so

v=\sqrt{\frac{1000-6.0*10^2}{2.1} } and

v=\sqrt{\frac{4.0*10^2}{2.1} } gives us

v = 14 m/s

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"1 Ampere" (A) means "1 coulomb of charge per second"

140 A means 140 coulombs per second

(140 coulomb/sec) x (0.9 sec)  =  126 coulombs of charge.


Go a little farther:

Electrons are the things that move through wire carrying charge.

6.25 x 10¹⁸ electrons carry 1 coulomb of charge. 

126 coulombs = 787,500,000,000,000,000,000 electrons (rounded)
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3 years ago
A liquid of low viscosity _____.
Thepotemich [5.8K]

Answer:

i believe B, my apologies if wrong, let me know if it was wrong so I can correct myself

Explanation:

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In each cycle, a heat engine performs 710 J of work and exhausts 1480 J of heat. What is the thermal effiency?
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Answer:

32%

Explanation:

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η = Wₒ / Qᵢ

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6 0
3 years ago
A 15-µF capacitor and a 25-µF capacitor are connected in parallel, and charged to a potential difference of 60 V. How much energ
Alborosie

Answer:

Energy stored, E = 0.072 J

Explanation:

Given that,

Capacitance, C_1=15\ \mu F

Capacitance, C_2=25\ \mu F

These two capacitor are connected in parallel, and charged to a potential difference of, V = 60 volts

We know that in parallel combination of capacitor, the equivalent capacitance is given by :

C=C_1+C_2\\\\C=(15+25)\ \mu F\\\\C=40\times 10^{-6}\ F

The energy stored in the capacitor is given by :

E=\dfrac{1}{2}CV^2\\\\E=\dfrac{1}{2}\times 40\times 10^{-6}\times (60)^2\\\\E=0.072\ J

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4 0
3 years ago
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Korolek [52]

Answer:

2C  charge will flow from ground and cloud

Explanation:

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Time is given as t=100\mu sec=100\times 10^{-6}=10^{-4}sec

WE have to find the how much charge flows between the ground and cloud in this time

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So 2C  charge will flow from ground and cloud

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