Momentum = mass * velocity
I need parts A and B to explain the intuitions.
When resistance is constant, current is proportional to voltage. When 1/3 the voltage is applied, 1/3 the current will result.
(1/3)*(1.2 A) = 0.4 A
The resulting current will be 0.4 A.
the answer would be B. the back emf increases, and the current drawn from the socket increases
more current is needed to make the motor move, like when you try to self crank a motor and the back wires are touching its harder to crank. and the emf increases since more current is being drawn in, strengthening the emf or increasing the emf
