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e-lub [12.9K]
3 years ago
10

A single-turn current loop, carrying a current of 3.50 a, is in the shape of a right triangle with sides 50.0, 120, and 130 cm.

the loop is in a uniform magnetic field of magnitude 72.5 mt whose direction is parallel to the current in the 130 cm side of the loop. what are the magnitude of the magnetic forces on each of the three sides?
Physics
1 answer:
dimulka [17.4K]3 years ago
3 0
Thank your very much
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One object is at rest, and another is moving. The two collide in a one-dimensional, completely inelastic collision. In other wor
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Answer:

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b) The final velocity is 9.0 m/s when the small-mass object is the one moving initially.

Explanation:

The momentum of the system is calculated as the sum of the momenta of each object. Each momentum is calculated as follows:

p = m · v

Where:

p =  momentum.

m =  mass.

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Then, the momentum of the system is the following:

m1 · v1 + m2 · v2 = (m1 + m2) · v

Where:

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m2 = mass of the smaller object.

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Solving the equation for the final velocity:

(m1 · v1 + m2 · v2)/ (m1 + m2) = v

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(7.1 kg · 29 m/s + 3.2 kg · 0)/(7.1 kg + 3.2 kg) = v

<u>v = 20 m/s</u>

b) When the smaller object is moving:

(7.1 kg · 0 m/s + 3.2 kg · 29 m/s) / (7.1 kg + 3.2 kg) = v

<u>v = 9.0 m/s</u>

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