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Vesnalui [34]
2 years ago
12

The equation for a parabola has the form y = ax2 + bx + c, where a, b, and c are constants and a ≠ 0. find an equation for the p

arabola that passes through the points (−1, −10), (1, −6), and (2, −13).
Mathematics
1 answer:
sattari [20]2 years ago
7 0
To solve the problem, substitute the given points for x in the given equation to get

-10=(-1)^2a+(-1)b+c\Rightarrow-10=a-b+c \\ -6=(1)^2a+(1)b+c\Rightarrow-6=a+b+c \\ -13=(2)^2a+(2)b+c\Rightarrow-13=4a+2b+c

Solving the three equations simultaneously, we have:

a = -3, b = 2 and c = -5

Therefore, the required equation is

y=-3x^2+2x-5
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F(x) = 4x+3x<br> g(x) = 2x-5<br> 7. Find (f+9) (x) <br> 8. Find (f - g) (x)
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