Write the general equation for the circle that passes through the points (1, 1), (1, 3), and (9, 2).
2 answers:
Answer:
Step-by-step explanation:
For point (1,1)
8*1^2+8*1^2+a*1+b*1+c=0
8+8+a+b+c=0
a+b+c=-16
For point (1,3):
8*1^2+8*3^2+a*1+b*3+c=0
8+72+a+3b+c=0
a+3b+c=-80
For point (9,2):
8*9^2+8*2^2+a*9+b*2+c=0
648+32+9a+2b+c=0
9a+2b+c=-680
From system:
a+b+c=-16.....(1)
a+3b+c=-80....(2)
9a+2b+c=-680....(3)
From (2)-(1) we have:
2b=-64
b=-32.
Now we have
a+c=16
9a+c=-616
i.e,
8a=-600,
a=-75,
and at the end
c=16+75=91
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