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3 years ago

Which of the following statements describes a way that simple machines make work easier?

Physics

2 answers:

Lapatulllka [165]3 years ago

7 0

It reduces the size

and changes the direction

Why because i just took and i got it wrong because the other person does not know the answer

Elina [12.6K]3 years ago

5 0

Pretty sure it's the last one:
"reduce the size of the input force needed to perform a task"

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Which equation can be used to solve for acceleration?<br> t=v/a<br> vf=at-vi<br> a=d/t<br> v=a/t

postnew [5]

Answer:

t=v/a

Explanation:

Acceleration is defined as the rate of change of velocity with time. It is mathematically expressed as;

Acceleration = $\frac{Final velocity - Initial velocity}{time}$

The change in velocity per unit of time is the acceleration

From this equation;

time = $\frac{change in velocity }{acceleration}$

This expression is analogous to the expression chosen.

3 0

3 years ago

The distance between the ruled lines on a diffraction grating is 1900 nm. The grating is illuminated at normal incidence with a

SashulF [63]

Answer:

3.28 degree

Explanation:

We are given that

Distance between the ruled lines on a diffraction grating, d=1900nm= $1900\times 10^{-9}m$

Where $1nm=10^{-9} m$

$\lambda_2=400nm=400\times10^{-9}m$

$\lambda_1=700nm=700\times 10^{-9}m$

We have to find the angular width of the gap between the first order spectrum and the second order spectrum.

We know that

$\theta=sin^{-1}(\frac{m\lambda}{d})$

Using the formula

m=1

$\theta_1=sin^{-1}(\frac{1\times700\times 10^{-9}}{1900\times 10^{-9}})$

$\theta=21.62^{\circ}$

Now, m=2

$\theta_2=sin^{-1}(\frac{2\times400\times 10^{-9}}{1900\times 10^{-9}})$

$\theta_2=24.90^{\circ}$

$\Delta \theta=\theta_2-\theta_1$

$\Delta \theta=24.90-21.62$

$\Delta \theta=3.28^{\circ}$

Hence, the angular width of the gap between the first order spectrum and the second order spectrum=3.28 degree

6 0

3 years ago

On an air track, a 400.5 g glider moving to the right at 2.30 m/s collides elastically with a 500.0 g glider moving in the oppos

Yanka [14]

Answer:

3.53 m/s towards the left

Explanation:

$m_1$ = Mass of first glider = 400.5 g

$m_2$ = Mass of Second glider = 500 g

$u_1$ = Initial Velocity of first object = 2.3 m/s

$u_2$ = Initial Velocity of second object = -2.95 m/s

As momentum and Energy is conserved

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}$

${\tfrac {1}{2}}m_{1}u_{1}^{2}+{\tfrac {1}{2}}m_{2}u_{2}^{2}={\tfrac {1}{2}}m_{1}v_{1}^{2}+{\tfrac {1}{2}}m_{2}v_{2}^{2}$

From the two equations we get

$v_{1}=\frac{m_1-m_2}{m_1+m_2}u_{1}+\frac{2m_2}{m_1+m_2}u_2\\\Rightarrow v_1=\frac{0.4005-0.5}{0.4005+0.5}\times 2.3+\frac{2\times 0.5}{0.4005+0.5}\times -2.95\\\Rightarrow v_1=-3.53\ m/s$

The velocity of first glider after collision is 3.53 m/s towards the left

4 0

3 years ago

Letters A B, C and D represent locations on a bar magnet. Which location has the greatest magnetic force? (l) A (3) C ets (2) B

Elena L [17]

Answer: The magnetic field of a bar magnet is strongest at either pole of the magnet. It is equally strong at the north pole compared with the south pole. The force is weaker in the middle of the magnet and halfway between the pole and the center. So it would be D.

6 0

3 years ago

___________ force can be thought of as either a push or a pull, as long as it makes the object move in a circular path.

fomenos

I believe it would be the Centripetal force.

5 0

3 years ago

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