Crest is the part of the wave which does this.
A sound wave is the sample of disturbance resulting from the movement of strength visiting through a medium, including air, water or every other liquid or stable remember as it propagates far from the supply of the sound.
The sound waves are generated by a sound source, such as the vibrating diaphragm of a stereo speaker. The sound source creates vibrations in the surrounding medium. because the supply continues to vibrate the medium, the vibrations propagate far from the supply at the rate of sound, hence forming the sound wave.
A sound wave is not a transverse wave with crests and troughs, however alternatively a longitudinal wave with compressions and rarefactions.
Learn more about wave here:- brainly.com/question/1199084
#SPJ1
Answer:
E = 169.34 J
Explanation:
First, we need to find the frictional force between the back tire and the road. For that purpose, we use the following formula:
f = μR = μW
f = μmg
where,
f = frictional force = ?
μ = coefficient of friction between tire and road = 0.8
g = 9.8 m/s²
m = mass supported by back tire = (0.5)(90 kg) = 45 kg
Therefore,
f = (0.8)(45 kg)(9.8 m/s²)
f = 352.8 N
Now, for the heat energy we use the formula of work. Because, thermal energy will be equal to work done by frictional force:
E = W = fd
where,
E = Thermal Energy = ?
f = frictional force = 352.8 N
d = displacement = 48 cm = 0.48 m
Therefore,
E = (352.8 N)(0.48 m)
<u>E = 169.34 J</u>
Answer:
16.6N
Explanation:
Given parameters:
Mass of rocket = 2000g = 2kg
Acceleration = 8.3m/s²
Unknown:
Force acting on the rocket = ?
Solution:
The force acting on a body can be derived from the product of its mass and acceleration;
Force = mass x acceleration
Insert the parameters and solve;
Force = 2 x 8.3 = 16.6N
Answer:
q = 27.16 C
Explanation:
For this exercise we use the equations of equilibrium. Let's set a reference system with the x-axis horizontally.
X axis
F_e - Tₓ = 0
Axis y
T_y -W = 0
let's use trigonometry
cos θ = T_y / T
sin θ= Tx / T
T_y = T cos θ
Tₓ = T sin θ
Axis y
T cos θ = W
T = mg / cos θ
X axis
F_e = T sin θ
qE = T sin θ
q =
q =
q =
in the exercise they indicate that the electric field is the month of birth E = 8 N / C and the angle tea = 30º
let's calculate
q = 0.2 9.8 8 / tan 30
q = 27.16 C