Initial velocity = Vo= 25 m/s
Final velocity = V = x
Acceleration= a = 6 m/s^2
time= t = 4 seconds
Appy the equation:
V = Vo + at
Replacing:
V = 25 + 6(4) = 25 + 24 = 49 m/s
Answer:
2.345 would be the most precious because you have more numbers to work with and exact numbers
Well velocity is a vector quanity and we can brake vectors in to verticle and horizantal componontes threw these two formulas Vcostheta=Vx and Vsintheta=Vy
Answer:
Explanation:
We can prove that this is a circular motion if we demonstrate that the norm of the vector is independent of time. Hence we have

but cos^2(3t)+sin^2(3t)=1. Thus we obtain

The norm is independent of t, thus, the particle describes a circular motion
Hope this helps!!
Answer:
the force between the two charges is 198.37 N
Explanation:
Given;
charge of the first particle, Q₁ = -3 x 10⁻⁵ C
charge of the second particle, Q₂ = 9.0 x 10⁻⁵ C
distance between the two charges, r = 0.35 m
The force between the two charges is calculated from Coulomb's law;

where k is Coulomb's constant = 9 x 10⁹ Nm²/C²

Therefore, the force between the two charges is 198.37 N