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Oliga [24]
4 years ago
7

Gravity is pulling on you downwards with a force which we call your weight. The reason why you aren't accelerating downwards is

that there is an equal and opposite force of the floor (let's assume you are standing up) pushing you upwards that nets out against the force of gravity. This is the "equal and opposite" force described by Newton's Third Law of Motion.?
Physics
1 answer:
VladimirAG [237]4 years ago
7 0

Answer:

No.

Explanation:

This force, that avoids that our body be accelerated downwards in spite of the attractive force from the earth, is called the normal force, as it is always normal to the surface on which the object is placed.

It is not the "equal and opposite force" described by Newton's Third Law of motion, because, this law says that this force acts on both bodies simultaneously, ( as a pair) so, one force is the one exerted by Earth on the body (which we call weight) and the other is exerted by us on Earth (acting at the center of the Earth, upward).

Also, the case when the normal force is equal and opposite to gravity force, is a special case, when the surface is level, and the object is at rest in the vertical direction.

Normal force can adopt any value so the combination of external forces be compliant with Newton's 2nd Law.

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Answer:

2. Galaxy

5. Electromagnetic radiation

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6 0
3 years ago
Imagine a universe in which, like in ours, there are two kinds of charges (positive and negative), with the like charges repelli
GuDViN [60]

Answer:

the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

Explanation:

In this hypothetical system the electric force is of type

       F = k' \frac{q_1 q_2 }{r^2}

in this case the force decays to zero much faster,

if we call Fo the force of Coulomb's law

         F₀ = k \frac{q_1 q_2 }{r^2}

assuming the constant k is the same

the relationship between the two forces is

        F / F₀ = 1 / r

        F = F₀ / r

when analyzing this expression the force decays much faster to zero.

In an electric conductor, charges of the same sign may not feel any repulsive force from other charges that are at a medium distance, so there is a probability that some charges are distributed in the volume of the material, this does not happen with coulomb's law

Consequently, the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

5 0
3 years ago
A 2.0 kilogram ball rolling along a flat surface starts up a hill. If the ball reaches a height of 0.63 meters, what was its ini
Agata [3.3K]
The potential energy as it reaches a height of 0.63 meters is mgh
Since total mechanical energy is conserved, Set that equal to the initial kinetic energy which is 0.5mv^2

2*9.8*0.63 = 0.5*2*v^2
12.348 = v^2
3.51 = v

That's it's initial speed.
5 0
3 years ago
Need help ??? Please
Yanka [14]
Is there information in the previous question which relates to this one?
8 0
3 years ago
A 3.00-kg object has a velocity 16.00 i ^ 2 2.00 j ^2 m/s.
trapecia [35]

Answer:

390 J

Explanation:

m = 3 kg

u = 16 i + 2 j

(a) Magnitude of velocity = \sqrt{16^{2}+2^{2}} = 16.1245 m/s

KEi = 1/2 m v^2 = 0.5 x 3 x 16.1245 = 390 J

(b) v = 18 i + 14 j

Magnitude of velocity =  \sqrt{18^{2}+14^{2}} = 22.804 m/s

KEf = 1/2 m v^2 = 0.5 x 3 x 22.804 = 780 J

According to the work energy theorem

Work done = change in KE = KEf - KEi = 780 - 390 = 390 J

8 0
4 years ago
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