Question

Excited lithium ions emit radiation at a wavelength of 670.8 nm in the visible range spectrum. Calculate the frequency of a photon of this radiation

Answer 1

Answer : The frequency of a photon of radiation is, $4.47\times 10^9s^{-1}$

Explanation : Given,

Wavelength of the radiation = 670.8 nm

First we have to convert wavelength form 'nm' to 'm'.

Conversion used : $(1nm=10^{-9}m)$

So, the wavelength of the radiation = 670.8 nm = $670.8\times 10^{-9}m$

Now we have to calculate the frequency of a photon of radiation.

Formula used : $\nu =\frac{c}{\lambda}$

where,

$\nu$ = frequency of a photon of radiation

$\lambda$ = wavelength of the radiation

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get the frequency of a photon of radiation.

$\nu =\frac{3\times 10^8m/s}{670.8\times 10^{-9}m}$

$\nu =4.47\times 10^9s^{-1}$

Therefore, the frequency of a photon of radiation is, $4.47\times 10^9s^{-1}$

Answer 2

Answer:

$f=4.47x10^5GHz$

Explanation:

Hello,

In this case, we relate the speed of light, wavelength and frequency via the shown below equation expressed in the proper SI system of units:

$f=\frac{c}{\lambda } =\frac{3x10^8m/s}{670.8nm*\frac{1x10^{-9}m}{1nm} } =4.47x10^{14}Hz*\frac{1GHz}{1x10^9Hz}\\ f=4.47x10^5GHz$

Best regards.