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2 years ago

12

A basketball player can leap upward 0.42 m. What is the magnitude of his initial velocity at the start of the leap? Use g=9.81 m

/s2.

1 answer:

Tatiana [17]2 years ago

8 0

Farmula 2gh=vf²-vi²
2×0.42×9.81=0²-vi²
8.2404=vi²
Vi=✓8.2404
Vi=2.87m/sec

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<u><em>(b) 1:1</em></u>

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<u></u>

<u>1. Formulae:</u>

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