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Alexxx [7]
3 years ago
12

A basketball player can leap upward 0.42 m. What is the magnitude of his initial velocity at the start of the leap? Use g=9.81 m

/s2.
Physics
1 answer:
Tatiana [17]3 years ago
8 0
Farmula 2gh=vf²-vi²
2×0.42×9.81=0²-vi²
8.2404=vi²
Vi=✓8.2404
Vi=2.87m/sec
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