A basketball player can leap upward 0.42 m. What is the magnitude of his initial velocity at the start of the leap? Use g=9.81 m
1 answer:
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Answer:
F = 3.20 N
Explanation:
Given:
Work done by child = 80.2 j
Distance that the car moves = 25.0 m
We need to find the force acting on the car.
Solution:
Using work done formula as.
Where:
W = Work done by any object.
F = Force (push or pull)
d = distance that the object moves.
Substitute in work done formula.
F = 3.20 N
Therefore, force acting on the car F = 3.20 N