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stellarik [79]
3 years ago
6

Parallel and series circuitsI am quite confused as to how I can tackle this question

Physics
1 answer:
emmainna [20.7K]3 years ago
4 0
Please see the solution in the attached drawing.
Read it from the top down.

If you ever come back again, with one that has
an AC source and an L or a C in the circuit, I'll
be looking for more than 5 points for that one.  :-) 

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The net reaction of the calvin cycle is the conversion of co2 into the three-carbon sugar g3p. Along the way, reactions rearrang
WINSTONCH [101]

The conversion of CO2 into the three-carbon sugar G3p is the Calvin cycle's net reaction.

<h3 /><h3>What is Calvin Cycle?</h3>

Calvin cycle uses ATP and NADPH, which are created during the light reaction, to decrease atmospheric carbon dioxide in 3C sugar; Three steps can be distinguished in the Calvin Cycle reaction:

Carboxylation: A reaction that is catalyzed by RUBISCO, where RUBIP is the CO2 acceptor, results in the formation of 6 molecules of PGA (phosphoglycerate).

Here, there are 6 molecules with 18 carbons in PGA and 3 molecules with 3 carbons in CO2.

Reduction: One molecule of the output, glyceraldehyde 3 phosphate, is used to create sugar while the remaining five molecules go through regeneration.

Here, one glyceraldehyde-3-phosphate molecule with three carbon atoms is present.

Regeneration: From glyceraldehyde 3 phosphate, CO2 acceptor (RUBIP) is generated.

Here, 3 molecules of RUBIP and 5 molecules of dihydroxy acetone phosphate each have 15 carbons.

Know more about the Calvin cycle here:

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7 0
11 months ago
<img src="https://tex.z-dn.net/?f=what%20%5C%3A%20is%20%5C%3A%20refraction%20%5C%3A%20of%20%5C%3A%20light%20%5C%3A%20%20%7B%3F%7
topjm [15]

When light passes through one transparent medium to another transperent medium it bends and that beding of light is know as refraction of light !

8 0
3 years ago
Read 2 more answers
Two ships of equal mass are 110 m apart. What is the acceleration of either ship due to the gravitational attraction of the othe
dusya [7]

Answer:

Acceleration of the ship, a=2.14\times 10^{-7}\ m/s^2

Explanation:

It is given that,

Mass of both ships, m=39000\ metric\ tons=39\times 10^6\ kg

Distance between two ships, d = 110 m

The gravitational force between two ships is given by :

F=G\dfrac{m^2}{d^2}

F=6.67\times 10^{-11}\ Nm^2/kg^2\times \dfrac{(39\times 10^6\ kg)^2}{(110\ m)^2}

F = 8.38 N

Let a is the acceleration. Now, using second law of motion as :

a=\dfrac{F}{m}

a=\dfrac{8.38\ N}{39\times 10^6\ kg}

a=2.14\times 10^{-7}\ m/s^2

So, the acceleration of either ship due to the gravitational attraction of the other is 2.14\times 10^{-7}\ m/s^2. Hence, this is the required solution.

7 0
3 years ago
A 25.0 g marble sliding to the right at 20.0 cm/s overtakes and collides elastically with a 10.0 g marble moving in the same dir
vovikov84 [41]
In collision that are categorized as elastic, the total kinetic energy of the system is preserved such that,

   KE1  = KE2

The kinetic energy of the system before the collision is solved below.

  KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
  KE1 = 6125 g cm²/s²

This value should also be equal to KE2, which can be calculated using the conditions after the collision.

KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)

The value of x from the equation is 17.16 cm/s.

Hence, the answer is 17.16 cm/s. 
6 0
3 years ago
Which of these is not a type of force?
coldgirl [10]
Inertia
the awnswer is inertia b
6 0
3 years ago
Read 2 more answers
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