Answer:
Explanation:
Given that,
Mass of the heavier car m_1 = 1750 kg
Mass of the lighter car m_2 = 1350 kg
The speed of the lighter car just after collision can be represented as follows
b) the change in the combined kinetic energy of the two-car system during this collision
substitute the value in the equation above
Hence, the change in combine kinetic energy is -2534.78J
To solve this problem we will apply Newton's second law and the principle of balancing Forces on the rope. Newton's second law allows us to define the weight of the mass, through the function
Here,
m = mass
a = g = Gravitational acceleration
Replacing we have that the weight is
Since the rope is taut and does not break, the net force on the rope will be zero.
Therefore the tensile force in the rope is 98N
Answer:
System software acts as a platform on which an application software program runs.
Answer:
F=2.47*10^{-10} N
Explanation:
The gravitational force is calculated by using
G: Cavendish constant = 6.67*10^{-12}Nm^2/kg^2
r=2.30cm=0.023m
M1=1.4kg
M2=14.0g=0.014kg
By replacing we have
F=2.47*10^{-10} N
hope this helps!!
Mechanical energy = Potential Energy + Kinetic Energy
if there is no friction, M.E. is conserved
as a ball falls, it is losing height. (P.E.=mgh , therefore P.E. will decrease)
the potential energy is transformed into kinetic energy which equals 1/2MV^2.
the increase in K.E. equals the decrease in P.E.
and the sum of both equals M.E.
thus mechanical energy is conserved.
hope this helps you.