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Flauer [41]
3 years ago
12

Assume your car reaches a speed of 21.7 m/s at a steady rate for 5.05 s after the light turns green. (a) What distance have you

traveled during this time? (b) What is your average speed during this time?
Physics
1 answer:
boyakko [2]3 years ago
3 0

Answer:

The distance and average speed are 54.79 m and 10.85 m.

Explanation:

Given that,

Speed = 21.7 m/s

Time = 5.05 s

(a). We need to calculate the distance

Firstly we will find the acceleration

Using equation of motion

v = u+at

a = \dfrac{v-u}{t}

Where, v = final velocity

u = initial velocity

t = time

Put the value in the equation

a = \dfrac{21.7-0}{5.05}

a = 4.297 m/s^2

Now, using equation of motion again

For distance,

s = ut+\dfrac{1}{2}at^2

s = 0+\dfrac{1}{2}\times4.3\times(5.05)^2

s=54.79\ m

The distance is 54.79 m.

(b). We need to calculate the average speed during this time

v_{avg}=\dfrac{D}{T}

Where, D = total distance

T = time

Put the value into the formula

v_{avg}=\dfrac{54.79}{5.05}

v_{avg}=10.85\ m/s

Hence, The distance and average speed are 54.79 m and 10.85 m.

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alukav5142 [94]

Answer: Energy dissipation

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3. A man hits a 0.2 kg golf ball with a force of 4
pogonyaev

Answer:

Force(f)= mass x acceleration

Acceleration (a) is the rate of change in velocity.

F=4N

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a=4/0.2

a=20m/s^2

Explanation:

8 0
3 years ago
The linear momentum of a truck of mass 5000 kg that is moving at a velocity of +30 m/a is ___ kg m/s
miv72 [106K]

Linear momentum of a truck is 1,50,000 kg.m/s

Explanation:

Linear momentum is the product of the mass and velocity of an object. It is a vector quantity, which have a magnitude and a direction.

Linear momentum is a property of an object which is in motion with respect to a reference point (i.e. any object changing its position with respect to the reference point).

It's SI units are kg.m/s

Linear momentum is a vector quantity.

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Given data mass = 5000 kg ; velocity = 30 m/s

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7 0
3 years ago
An electron is accelerated within a particle accelerator using a 100 MV electric potential. The 100 MeV electron moves along an
Delicious77 [7]

Answer:

The length of the tube is 3.92 m.

Explanation:

Given that,

Electric potential = 100 MV

Length = 4 m

Energy = 100 MeV

We need to calculate the value of \gamma

Using formula of relativistic energy

E=m_{0}c^2(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)

Put the value into the formula

1.6\times10^{-15}= 9.1\times`10^{-31}\times9\times10^{16}(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)

(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)=\dfrac{1.6\times10^{-15}}{9.1\times10^{-31}\times9\times10^{16}}

Here, \gamma-1=(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)

\gamma-1=0.01953

\gamma=0.01953+1

\gamma=1.01953

We need to calculate the length

Using formula of length

L'=\dfrac{L}{\gamma}

Put the value into the formula

L'=\dfrac{4}{1.01953}

L'=3.92\ m

Hence, The length of the tube is 3.92 m.

8 0
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Answer:

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