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gregori [183]
3 years ago
8

The value of gravitational acceleration of a body on earth is 9.8m/s^2. The gravitational potential energy for a 1.00 kilogram o

bject is found to be 12.5 joules. How high is this object above the ground, where PE=0?
Physics
1 answer:
emmasim [6.3K]3 years ago
4 0

Answer:

The object is 1.2755 meters above the ground

Explanation:

Recall the formula for gravitational potential energy for an object of mass "m" at a height "h" above the ground:

PE=m\,*\,g\,*\,h

In this case, since we are given the mass of the object and the object's potential energy, we can estimate the only unknown (height "h") from the formula shown above. Also since all units are given in the SI system, the result for the object's height will result in meters:

PE=m\,*\,g\,*\,h\\12.5\,J=1.0\,kg\,*9.8\,\frac{m}{s^2} \,*\,h\\\frac{12.5}{9.8} \,meters= h\\h=1.2755\ meters

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Answer: 16N

Explanation:

Given that:

mass of box M= 2 kg

Initial speed V1 = 4 m/s

Final speed V2 = 8 m/s

Time taken T= 0.5 s

Average strength of this force F = ?

Now, recall that Force is the rate of change of momentum per unit time

i.e Force = momentum / time

Hence, F = M x (V2 - V1)/T

F = 2kg x (8 m/s - 4 m/s) / 0.5s

F = 2kg x (4 m/s / 0.5s)

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Thus, the average strength of this

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An elevator cab and its load have a combined mass of 1600 kg. Find the tension in the supporting cable when the cab, originally
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The tension in the supporting cable when the cab originally moves downward is 18422.4 N

What is tension?

Tension is described as the pulling force by the means of a three-dimensional object.

Tension might also be described as the action-reaction pair of forces acting at each end of said elements.

Here,

m =combined mass = 1600 kg

s = Displacement of the elevator = 42 m

g = Acceleration due to gravity = 9.81 m/s²

u = Initial velocity = 12 m/s

v = Final velocity = 0

According to the equation of motion:

v^{2} - u^{2} = 2as

0 - 12^2 = 2*a*42

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a = - 1.714 m/s^2

Now let's write the equation of the forces acting on the elevator. Taking upward as positive direction:

T-mg = ma

T = m(g-a)

T = 1600 ( 9.8-(-1.74))

T=18422.4 N

Hence,

The tension in the supporting cable when the cab, originally moving downward is 18422.4 N

Learn more about tension here:

<u>brainly.com/question/13772148</u>

#SPJ4

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