Question

Write the equation in standard form for a circle with center (-4.7) and tangent to the x-axis.

Answer 1

The equation of circle with centre at (-4,7) and tangent to x-axis is:

$(x+4)^2+(y-7)^2 = 49$

Further explanation:

Given

$Centre=(h.k) = (-4,7)$

As the circle is tangent to x-axis, its radius will be equal to the y-intercep or y- coordinate of the centre.

So,

r = y-coordinate= 7

The standard equation of circle is:

$(x-h)^2+(y-k)^2 = r^2$

Putting the values of h, k and r

$(x-(-4))^2+(y-7)^2 = (7)^2\\(x+4)^2+(y-7)^2 = 49$

Hence the equation of circle with centre at (-4,7) and tangent to x-axis is:

$(x+4)^2+(y-7)^2 = 49$

Keywords: Tangents, Equation of circle

Learn more about equations of circles at:

• brainly.com/question/1388658
• brainly.com/question/1357167

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