F ` ( x ) = ( x² )` · e^(5x) + x² · ( e^(5x) )` =
= 2 x · e^(5x) + 5 e^(5x) · x² =
= x e^(5x) ( 2 + 5 x )
f `` ( x ) = ( 2 x e^(5x) + 5 x² e^(5x) ) ` =
= ( 2 x ) ˙e^(5x) + 2 x ( e^(5x) )` + ( 5 x² ) ` · e^(5x) + ( e^(5x)) ` · 5 x² =
= 2 · e^(5x) + 10 x · e^(5x) + 10 x · e^(5x) + 25 x² · e^(5x) =
= e^(5x) · ( 2 + 20 x + 25 x² )
Answer:
<em>2.983 </em>ft/sec
Step-by-step explanation:
Given that
Distance between center and Jasmine riding on a carousal = 9.5 feet
Time taken to complete one rotation = 20 seconds
To find:
Jasmine's linear speed = ?
Solution:
Number of revolutions per minute = 
Formula for linear speed is given as:

Where
is the radius of circular path and
is the number of revolutions per minute.

Therefore, the linear speed is <em>2.983 ft/sec.</em>
Answer:8
Step-by-step explanation:
You find the average which is adding them all together then dividing by how many numbers you added.
Answer:
40cm²
Step-by-step explanation:
pretty sure bc there are 8 equal 5 cm² pieces meaning you multiply by 8 for the answer. 5•8=40. I think rofl