Answer:
a) 
is a solution of the linear equation.
b) The rate of change of the equation is 3.
c) The y-intercept of the equation is -2.
d) <em>Jayne is working in the grocery one day, according to her calculations, renting the lot costs 2 dollars per day and she could earn 3 dollars per hour by selling pastries. How much money does she earn after working 8 hours?</em>
Step-by-step explanation:
a) If is a solution of the linear equation, then 
. If 
, then the function evaluated at this value is:
Hence, is a solution of the linear equation.
b) The rate of change of the equation is represented by the slope of the function, which is the constant that multiplies the indepedent variable (
). Hence, the rate of change of the equation is 3.
c) The y-intercept of the equation is the only constant of the equation. Hence, the y-intercept of the equation is -2.
d) A real-world scenario would be the following: <em>Jayne is working in the grocery one day, according to her calculations, renting the lot costs 2 dollars per day and she could earn 3 dollars per hour by selling pastries. How much money does she earn after working 8 hours?</em>
Answer:
Step-by-step explanation:
eq. of circle is x²+y²+2gx+2fy+c=0
center=(-g,-k)
given eq. is x²+y²+4x-8y+11=0
comparing
2gx=4x
g=2
2fy=-8y
f=-4
center=(-2,4)
The sum of the set of x - values given to us is calculated as; ∑X = -1
<h3>How to find the the sum of a set of data?</h3>
We are given;
X1 = 2, X2 = -8, X3 = 4, X4 = -8 and Y1 = -3, Y2 = -8, Y3 = 10, Y4 = 6
1) ∑X = X1 + X2 + X3 + X4
∑X = 2 + (-8) + 4 + 1 = -1
2) ∑Y = Y1 + Y2 + Y3 + Y4
∑Y = 3 + (-8) + 10 + 6
∑Y = -11
3) ∑ X² = X₁² + X₂² + X₃² + X₄²
∑X² = (2)² + (-8)² + (4)² + (1)²
∑X² = 85
4) ∑Y² = Y₁² + Y₂² + Y₃² + Y₄²
∑X² = (-3)² + (-8)² + (10)² + (6)²
∑X² = 209
Complete question is;
Two variables, X and Y assume the values X1 = 2, X2 = -5, X3 = 4, X4 = 1 and Y1 = -3, Y2 = -8, Y3 = 10, Y4 = 6, respectively. Calculate (a) ∑X, (b) ∑ Y, (c) ∑ X² (d) ∑ Y²
Read more about Sum of data at; brainly.com/question/15858152
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Answer:
The correct options are:
Interquartile ranges are not significantly impacted by outliers.
Lower and upper quartiles are needed to find the interquartile range.
The data values should be listed in order before trying to find the interquartile range.
The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range.
The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median
