Yes I think it really is the correct answer
The quadratic formula is -b plus minus the square root of b^2-4ac all over 2a.
Here, a=1, b=13, and c=30.
The only option that fills in the values correctly is D
Segment BD equals 12<span />
Answer:
D
Step-by-step explanation:
<h3>
Answer: 1</h3>
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Explanation:
We're given the height in relation to base BC, so we need to find the length of this base. This is the same as finding the distance from B to C.
Turn to the distance formula

Coincidentally, the base and height are the same. This won't always be the case.
Now we can find the area of the triangle

The area of the triangle is 1 square unit.
See diagram below.