Answer:
34.45m
Explanation:
Magnitude of a vector is equal to the square root of sum of squares of x & y vectors.
Magnitude =
=
=34.45m
Explanation:
Let us assume that the maximum allowable horizontal distance be represented by "d".
Therefore, torque equation about A will be as follows.
d =
d = 0.409 m
Thus, we can conclude that the maximum allowable horizontal distance from the axle A of the wheelbarrow to the center of gravity of the second bag if she can hold only 75 N with each arm is 0.409 m.
Decibels I believe? I’m not 100% sure
The tralational equilibrium condition allows finding that the electric potential is V = 4.8 10¹¹ V
Given parameter
- The mass m = 1.5 g = 1.15 10-3 kg
- The charge on the sphere q = 8.9 10-16 C
- Plate spacing d = 5 cm = 5.00 10-2 m
To find
Newton's second law states that the force is proportional to the mass and the acceleration of the bodies, in the special case that the acceleration is zero, it establishes the condition for the equilibrium of the bodies
∑ F = 0
Where the bold indicate vector and F is the force
To use this equation we must fix a reference system with respect to which to carry out the decomposition and measurements of the forces; let's fix a system with the horizontal x axis and the vertical y axis, in the attachment I could see a free body diagram.
x- axis
Fe - Tₓ = 0
Fe = Tₓ
y-axis
- W = 0
W =
mg =
The electric force is
Fe = q E = q V / d
let's use trigonometry to decompose the stress
cos 30 = / T
sin 30 = Tₓ / T
= T cos 30
Tₓ = T sin 30
We substitute
q V / d = T sin 30
mg = T cos 30
It's solve the system of equations
= tan 30
V =
It's calculate
V =
V = 4.768 10¹¹ V
In conclusion, using the equilibrium condition, we could find that the electric potential is V = 4.8 10¹¹ V
Learn more about equilibrium condition here:
brainly.com/question/1967702