Explanation:
Given that,
Mass if the rock, m = 1 kg
It is suspended from the tip of a horizontal meter stick at the 0-cm mark so that the meter stick barely balances like a seesaw when its fulcrum is at the 12.5-cm mark.
We need to find the mass of the meter stick. The force acting by the stone is
F = 1 × 9.8 = 9.8 N
Let W be the weight of the meter stick. If the net torque is zero on the stick then the stick does not move and it remains in equilibrium condition. So, taking torque about the pivot.

W = 3.266 N
The mass of the meters stick is :

So, the mass of the meter stick is 0.333 kg.
Answer:
1020g
Explanation:
Volume of can=

Mass of can=80g=
1Kg=1000g
Density of lead=
By using 
We have to find the mass of lead which shot can it carry without sinking in water.
Before sinking the can and lead inside it they are floating in the water.
Buoyancy force =

Where
Density of water
Mass of can
Mass of lead
Volume of can
Substitute the values then we get




Hence, 1020 grams of lead shot can it carry without sinking water.
For Mass
K.E = (1/2*mv^2)
Explanation:
Kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.
Answer:
Maximum height, h = 10 m
Explanation:
It is given that,
Mass of golf ball, m = 45 g = 0.045 kg
The ball comes down on a tree root and bounces straight up with an initial speed of 14.0 m/s.
We need to find the height the ball will rise after the bounce. It is based on the conservation of energy such that,

h is maximum height raised by the ball

So, the ball will raised to a height of 10 meters.