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3 years ago

How far will you travel if you run for 10 minutes at 2 m/s? SHOW WORK PLZS

Physics

1 answer:

ella [17]3 years ago

7 0

10 minutes are the same as 600 seconds.

If you run 2 meters in 1 second then you run 2 * 600 meters in 600 seconds.

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A sound wave has a speed of 345 m/s and a wavelength of 4.15 meters. What is the frequency of this wave?

Debora [2.8K]

Answer:

83 hertz

OPTION A

Explanation:

$wavelength = \frac{speed}{frequency}$

Given

wavelength=4.15m

speed=345 m/s

$frequency = \frac{speed}{wavelength} = \frac{345}{4.15}$

$frequency = 83 \: hertz$

I hope it helped you

5 0

3 years ago

A 200kg ball on the end of string is swung in horizontal circle with radius of 0.5m . The ball makes revolution every 2second th

ANEK [815]

Answer: $\dfrac{\pi}{2} ms^{-1}$

Explanation:

Let $T$ be the time required to make one revolution.

Let $r$ be the radius of the circular path.

Let $d$ be the distance travelled by ball in one revolution.

As we know,the distance travelled in one revolution is the circumference of the circle.

So, $d=2\pi r$

Given, $d=0.5m\\T=2sec$

$d=2\times \pi \times 0.5=\pi m$

Speed of an object moving is circular path is define as the ratio of distance travelled in one revolution to the time taken by the object to complete one revolution.

Let $s$ be the speed of the ball.

$s=\frac{d}{T}=\frac{\pi }{2}ms^{-1}$

So,the speed of the ball is $\frac{\pi }{2}ms^{-1}$

5 0

3 years ago

What’s 4.5 inches into centimeters?

marshall27 [118]

Answer:

11.43 cm

Explanation:

yes

3 0

4 years ago

Read 2 more answers

A truck starts off 151 miles directly north from the city of Hartville. It travels due east at a speed of 41 miles per hour. Aft

Bess [88]

Answer:

9.51

Explanation:

The distance s is given by:

$s(t) = \sqrt{151^2 + (vt)^2}$

The change in distance is given by the time derivative of s:

$\frac{ds}{dt} = \frac{v^2t}{\sqrt{151^2 + (vt)^2}}$

For the time t you solve the equation of distance x for time:

$x = vt => t = \frac{x}{v}$

Plugging in for t:

$\frac{ds}{dt}(t=\frac{x}{v})=\frac{vx }{\sqrt{151^2 + x^2}}=9.51$

6 0

3 years ago

Two gliders collide on an air track moving in from opposite directions, and they bounce back. The masses of the gliders are 0.20

timurjin [86]

Answer:

so initial momentum is 0.22kgm/s

Explanation:

m1=0.20kg

m2=0.30kg

initial velocity of m1=u1=0.50m/s

initial velocity of m2=u2=0.40m/s

total momentum of the system before collision

Pi=m1u1+m2u2

Pi=0.20kg×0.50m/s+0.30kg×0.40m/s

Pi=0.1kgm/s+0.12kgm/s

Pi=0.22kgm/s

3 0

3 years ago