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lara [203]
2 years ago
14

The label on a soft drink bottle gives the volume in two units: 2.0 L and 67.6 fl oz. Use this information to derive a conversio

n factor between the English and metric units.
Chemistry
1 answer:
svetoff [14.1K]2 years ago
5 0

Answer:

Let's look at another example: 3/4 is the same as 6/8. How do you know this to be true? The proof is in the pie chart diagram. The top circle has 3 out of the 4 parts shaded in. The bottom circle has 6 of the 8 parts shaded in. However, both fractions refer to the same part of the circle.

You can check your results by dividing. Here, both the numerator (6) and the denominator (8) are divisible by 2.

Finding 2nd Fraction Numerators

What would happen if a numerator were missing? Well, if you're given two fractions and told that they are equivalent fractions, you can find the missing numerator using multiplication or division.

In all equivalent fractions, both the numerator and denominator of the first fraction can be multiplied by the same number to get the numerator and denominator of the second fraction.

Say one of the numerators was missing from those pie chart equations:

3 / 4 = x / 8

You can see that there is an x alongside one of the numerators. That represents the number you are trying to find.

The answer lies in discovering what the first denominator can be multiplied by to get the other denominator. You might be good enough at your times tables to know that 4 times 2 is 8. But you can also check this number by dividing the denominator (8) by the denominator (4), which equals 2.

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If 40.0 mL of a calcium nitrate solution reacts with excess potassium carbonate to yield 0.524 grams of a precipitate, what is t
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Explanation :

The balanced chemical reaction is:

Ca(NO_3)_2+K_2CO_3\rightarrow CaCO_3+3KNO_3

When calcium nitrate react with potassium carbonate to give calcium carbonate as a precipitate and potassium nitrate.

First we have to calculate the moles of CaCO_3

\text{Moles of }CaCO_3=\frac{\text{Mass of }CaCO_3}{\text{Molar mass of }CaCO_3}

Given:

Mass of CaCO_3 = 0.524 g

Molar mass of CaCO_3 = 100 g/mol

\text{Moles of }CaCO_3=\frac{0.524}{100g/mol}=0.00524mol

Now we have to calculate the concentration of CaCO_3

\text{Concentration of }CaCO_3=\frac{\text{Moles of }CaCO_3}{\text{Volume of solution}}=\frac{0.00524mol}{0.040L}=0.131M

Now we have to calculate the concentration of calcium ion.

As, calcium carbonate dissociate to give calcium ion and carbonate ion.

CaCO_3\rightarrow Ca^{2+}+CO_3^{2-}

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Concentration of calcium ion = Concentration of CaCO_3 = 0.131 M

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