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lara [203]
2 years ago
14

The label on a soft drink bottle gives the volume in two units: 2.0 L and 67.6 fl oz. Use this information to derive a conversio

n factor between the English and metric units.
Chemistry
1 answer:
svetoff [14.1K]2 years ago
5 0

Answer:

Let's look at another example: 3/4 is the same as 6/8. How do you know this to be true? The proof is in the pie chart diagram. The top circle has 3 out of the 4 parts shaded in. The bottom circle has 6 of the 8 parts shaded in. However, both fractions refer to the same part of the circle.

You can check your results by dividing. Here, both the numerator (6) and the denominator (8) are divisible by 2.

Finding 2nd Fraction Numerators

What would happen if a numerator were missing? Well, if you're given two fractions and told that they are equivalent fractions, you can find the missing numerator using multiplication or division.

In all equivalent fractions, both the numerator and denominator of the first fraction can be multiplied by the same number to get the numerator and denominator of the second fraction.

Say one of the numerators was missing from those pie chart equations:

3 / 4 = x / 8

You can see that there is an x alongside one of the numerators. That represents the number you are trying to find.

The answer lies in discovering what the first denominator can be multiplied by to get the other denominator. You might be good enough at your times tables to know that 4 times 2 is 8. But you can also check this number by dividing the denominator (8) by the denominator (4), which equals 2.

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Answer:

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2 years ago
What is the difference between hypertonic and hypotonic
Bess [88]
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2 years ago
Calculate the mass defect for the formation of phosphorus-31. The mass of a phosphorus-31 nucleus is 30.973765 amu. The masses o
Nata [24]

<u>Answer:</u> The mass defect for the formation of phosphorus-31 is 0.27399

<u>Explanation:</u>

Mass defect is defined as the difference in the mass of an isotope and its mass number.

The equation used to calculate mass defect follows:

\Delta m=[(n_p\times m_p)+(n_n\times m_n)]-M

where,

n_p = number of protons

m_p = mass of one proton

n_n = number of neutrons

m_n = mass of one neutron

M = mass number of element

We are given:

An isotope of phosphorus which is _{15}^{31}\textrm{P}

Number of protons = atomic number = 15

Number of neutrons = Mass number - atomic number = 31 - 15 = 16

Mass of proton = 1.00728 amu

Mass of neutron = 1.00866 amu

Mass number of phosphorus = 30.973765 amu

Putting values in above equation, we get:

\Delta m=[(15\times 1.00728)+(16\times 1.00866)]-30.973765\\\\\Delta m=0.27399

Hence, the mass defect for the formation of phosphorus-31 is 0.27399

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3 years ago
For the following reaction, identify the element that was oxidized, the element that was reduced, and the reducing agent. Give a
Volgvan

<span>For this reaction, oxidation number of Carbon in CO would be +2 while oxidation number of carbon in CO2 would be +4 and so this means that carbon has oxidized. Oxidation number of nitrogen in NO is +2. While oxidation number of nitrogen in N2 is 0 so this means that nitrogen had reduced. The reducing agent is the one which provides electrons by oxidizing itself so in this case; CO is the reducing agent while the C in CO oxidized to produce electrons. </span><span>I am hoping that this answer has satisfied your query about and it will be able to help you, and if you’d like, feel free to ask another question.</span>

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3 years ago
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