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2 years ago

Calculate the volume occupied by 10 moles of hydrogen gas at 145K and 705 Torr.

Chemistry

1 answer:

Norma-Jean [14]2 years ago

4 0

The volume occupied by 10 moles of hydrogen gas at 145K and 705 Torr is 128.01L.

<h3>How to calculate volume?</h3>

The volume of a gas can be calculated using ideal gas law equation as follows:

PV = nRT

Where;

P = pressure
V = volume
n = number of moles
R = gas law constant
T = temperature

P = 705torr = 0.93atm
V = ?
T = 145K
n = 10
R = 0.0821 Latm/molK

0.93 × V = 10 × 0.0821 × 145

0.93V = 119.05

V = 128.01L

Therefore, the volume occupied by 10 moles of hydrogen gas at 145K and 705 Torr is 128.01L.

Learn more about volume at: brainly.com/question/13338592

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The densities of gases a, b, and c at stp are 1.25 g/l, 2.86 g/l and 0.714 g/l, respectively. calculate the molar mass of each s

kicyunya [14]

The molar mass of a, b and c at STP is calculated as below

At STP T is always= 273 Kelvin and ,P= 1.0 atm

by use of ideal gas equation that is PV =nRT
n(number of moles) = mass/molar mass therefore replace n in the ideal gas equation

that is Pv = (mass/molar mass)RT
multiply both side by molar mass and then divide by Pv to make molar mass the subject of the formula

that is molar mass = (mass x RT)/ PV

density is always = mass/volume

therefore by replacing mass/volume in the equation by density the equation
molar mass=( density xRT)/P where R = 0.082 L.atm/mol.K

the molar mass for a
= (1.25 g/l x0.082 L.atm/mol.k x273k)/1.0atm = 28g/mol

the molar mass of b
=(2.86g/l x0.082L.atm/mol.k x273 k) /1.0 atm = 64 g/mol

the molar mass of c

=0.714g/l x0.082 L.atm/mol.K x273 K) 1.0atm= 16 g/mol

therefore the
gas a is nitrogen N2 since 14 x2= 28 g/mol
gas b =SO2 since 32 +(16x2)= 64g/mol
gas c = methaneCH4 since 12+(1x4) = 16 g/mol

8 0

3 years ago

Who is wise president of india?<br>________________________

MariettaO [177]

The vise president of India is M. Venkaiah Naidu

5 0

3 years ago

Nitrogen forms a surprising number of compounds with oxygen. A number of these, often given the collective symbol NOx (for "nitr

kvv77 [185]

Answer:

9.2

Explanation:

Let's do an equilibrium chart of this reaction:

2NO(g) + O₂(g) ⇄ 2NO₂(g)

4.9 atm 5.1 atm 0 Initial

-2x -x +2x Reacts (stoichiometry is 2:1:2)

4.9-2x 5.1-x 2x Equilibrium

The mole fraction of NO₂ (y) can be calculated by the Raoult's law, that states that the mole fraction is the partial pressure divided by the total pressure:

y = 2x/(4.9 - 2x + 5.1 -x + 2x)

0.52 = 2x/(10 - x)

2x = 5.2 -0.52x

2.52x = 5.2

x = 2.06 atm

Thus, the partial pressure at equilibrium are:

pNO = 4.9 -2*2.06 = 0.78 atm

pO₂ = 5.1 - 2.06 = 3.04 atm

pNO₂ = 2*2.06 = 4.12 atm

Thus, the pressure equilibrium constant Kp is:

Kp = [(pNO₂)²]/[(pNO)²*(pO₂)]

Kp = [(4.12)²]/[(0.78)²*3.04]

Kp = [16.9744]/[1.849536]

Kp = 9.2

4 0

3 years ago

Well, we might as well try a similar question. Magnesium metal reacts with hydrochloric acid to produce hydrogen gas and an aque

Andrei [34K]

Answer: Magnesium Mg

Explanation:

Oxidization is the process by which a substance either gains oxygen or losses electrons.

The chemical reaction of the above is denoted by,

Mg(s) + 2HCl(aq) -----> MgCl2(aq) + H2(g)

Mg went from a 0 to a +2 state which would mean that it lost electrons.

It was therefore oxidized.

Please do react or comment if you need clarification or if the answer helped you. This can help other users as well. Thank you.

5 0

3 years ago

If the reaction 2HgO --> 2Hg + O2 is endothermic, which bonds are the strongest?

Alika [10]

Endothermic reaction means the reactant side takes heat from surrounding and get decomposed i.e ∆H=-ve
If the equation is exothermic then it means the reactant is happy to decompose .But it's not as it's endothermic

Now

HgO is Omitted from our solution option.

Hg is a atom so no bonds hence no bond strength occurs.

O_2 is a molecule and so it's our answer .

3 0

2 years ago