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3 years ago

Exposure to the Sun's harmful infrared radiation should be kept to a minimum.

1 answer:

7 0

Of course! If it's harmful, then your exposure to it should be kept
to a minimum. That's a no-brainer. But the sun's infrared radiation
is generally less harmful than its ultraviolet radiation is.

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A positively-charged object with a mass of 0.129 kg oscillates at the end of a spring, generating ELF (extremely low frequency)

9966 [12]

Answer:308 N/m

Explanation:

Given

mass $\left ( m\right )=0.129 kg$

wavelength $\left ( \lambda \right )=3.86\times 10^7$

We know frequency = $\frac{c}{\lambda }=\frac{3\times 10^8}{3.86\tmes 10^7}$

f=7.772 Hz

As the frequency of radio waves is same as the frequency at which object oscillates

$f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}$

$7.772=\frac{1}{2\pi }\sqrt{\frac{k}{0.129}}$

$7.772\times 2\times \pi =\sqrt{\frac{k}{0.129}}$

$k=307.70\approx 308 N/m$

7 0

3 years ago

XERCISE

kkurt [141]

The answer is Anguer...

Hope it helps... pls mark brainliest

3 0

2 years ago

At what distance will a 80 W lightbulb have the same apparent brightness as a 120 W bulb viewed from a distance of 40 m

liq [111]

Answer:

32.6mm

Explanation:

Using area of a sphere(bulb) = 4πr²

So A is proportional to radius²

So the Energy will be proportional to r²

But 120/80 = 1.5 is the energy factor so

Using

1.5/d² = 1/r²

1.5/40²= 1/r^2

r = √( 40²/ 1.5)

r = 32.6m

4 0

2 years ago

What injuries could occur due to incorrect movement and handling of equipment with any sport or activity? (Select ALL that apply

NeTakaya

Sprains/Strains, tears to muscles, tendons ligaments, not hypothermia bc thats when you get really cold and not dehydrated

4 0

3 years ago

PLEASE HELP! DUE DATE IS TODAY

g100num [7]

Answer:

Question 2

Part (a)

Chlorine: type of compound = chloride

Oxygen: type of compound = oxide

Part (b)

The iron reacts with water and oxygen to form rust.

A water molecule is made up of two hydrogen atoms joined to one oxygen atom: Di-hydrogen oxide.

Question 3

This circuit is in parallel.

The current in a parallel circuit splits into different branches then combines again before it goes back into the supply.

We are told that A₁ = 0.8 A

As the lamps have equal resistance, the current splits equally:

A₂ = 0.4 A

A₃ = 0.4 A

Then combines again:

A₄ = 0.8 A

4 0

2 years ago