Answer:
The speed of the other piece of the object is 13/4*v0, going to the right.
Explanation:
Assuming that no external forces acting during the explosion (as the time during which it happens is considered infinitesimal), total momentum must be conserved , same as it happens with the total mass, assuming that v₀ is much smaller than c (speed of light), so no conversion of mass into energy is done.
So, based on the information provided, we can write the following expression, assuming the positive direction to be the one to the right:
m*v₀ = -3/5*m*(v₀/2) + 2/5*m*vₓ
Solving for vₓ, we have:
vₓ = 13/4*v₀, to the right, as the value obtained is positive.
Answer:
This is false
Explanation:
This is why the answer to this question is false. If these types of objects (2 points connected) should pass through same sets of 3 points, irrespective of the order that each object was plotted, we will not get identical shapes created.
The shape that is going to be created will be dependent on the pattern/order that was involved in the plotting. If it was identical, then we will have identical shapes. But if the order during plotting is different then we will have different shapes created.
Thank you!
Answer:
23.246 metres per second
Explanation:
divide the speed value by 2.237
To solve this problem we need the concepts of Energy fluency and Intensity from chemical elements.
The energy fluency is given by the equation
Where
The energy fluency
c = Activity of the source
r = distance
E = electric field
In the other hand we have the equation for current in materials, which is given by
Then replacing our values we have that
We can conclude in this part that 1.3*10^7Bq is the activity coming out of the cylinder.
Now the energy fluency would be,
The uncollided flux density at the outer surface of the tank nearest the source is
You started out by telling us that the block of paraffin has
10 cm³ of volume. When it's completely submerged, it displaces
10 cm³ of gasoline. Each cm³ of gasoline weighs 0.0069N, so
the whole 10 of them weigh (10 x 0.0069) = 0.069 N.
We notice that the block of paraffin weighs more than the gasoline
that it displaces. So there's no doubt about it ... the paraffin sinks
in gasoline.
If you were to drop it into water instead, it wouldn't sink. Each
cm³ of water weighs 0.0098 N, and 10 of those weigh 0.098N.
In water, the paraffin would settle down only until it displaced
its own weight ... 0.085 N, about 8.7 cm³ of water ... and then
it would float right there, with about 87% of it under water and
the other 13% of it above the surface.