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sdas [7]
3 years ago
8

How many meters in 2.50 miles? (Use these two conversions: 1000 m = 1 km and 1.00 km = .621 mi )

Physics
1 answer:
Artyom0805 [142]3 years ago
7 0

2.50 miles is equal to 4026 m.

<u>Explanation:</u>

As it is known that 1000 m =1 km and 1 km = 0.621 miles. So first we have to convert miles to km and then to metre as follows.

As 1 km = 0.621 miles, then

             \text { 1 miles }=\frac{1}{0.621} \mathrm{km}

So, 2.50 miles will be equal to

            2.50 \text { miles }=\frac{2.50}{0.621} \mathrm{km}=4.026 \mathrm{km}

Then, in order to get the answer in meters, we have to convert this km to meter by the conversion of 1000 m =1 km.  So,

           1 \mathrm{km}=1000 \mathrm{m}

Thereby,

          4.026 \mathrm{km}=4026 \mathrm{m}

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a ball is thrown down at 25 m/s from a 500m tall building. how fast is it traveling when it hits the ground?
Mrrafil [7]

Answer:

The speed of the ball when it hits the ground is 102.1 m/s

Explanation:

Given;

initial velocity of ball, u = 25 m/s

distance traveled by the ball = height of the building = h = 500 m

when the ball hits the ground, the final velocity, v = ?

The final velocity of the ball is given by;

v² = u² + 2gh

where;

g is acceleration due to gravity = 9.8 m/s²

v² = (25)² + 2(9.8)(500)

v² = 10425

v = √10425

v = 102.1 m/s

Therefore, the speed of the ball when it hits the ground is 102.1 m/s

3 0
3 years ago
3.5 g of a hydrocarbon fuel is burned in a vessel that contains 250. grams of water initially at 25.00 C. After the combustion,
kherson [118]

Answer:

3.) 463 J/g

Explanation:

Heat given by the fuel is used to increase the temperature of the water

so it is given as

Q = ms\Delta T

here we will have

m = 250 g

\Delta T = 26.55 - 25

now we also know that

s = 4186

so we have

Q = (0.250)(4186)(26.55 - 25)

Q = 1622.075 J

so 3.5 g fuel gives above energy

so per gram of fuel will have total energy given as

Q = \frac{1622.075}{3.5}

Q = 463.45 J/g

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A convex lens with a focal length of 10 cm is located 30 cm away from a
zloy xaker [14]

Answer: 15 cm

Explanation:

According to the Lens Equation we have the following:

\frac{1}{f}=\frac{1}{v}+\frac{1}{u} (1)

Where:

f=10 cm is the focal length

u=30 cm is the distance between the candle (the object) and the lens

v is the distance between the image and the lens

Isolating v:

v=\frac{uf}{u-f}} (2)

Solving:

v=\frac{(30 cm)(10 cm)}{30 cm-10 cm}} (3)

Finally:

v=15 cm This is where the image is located

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3 years ago
The diagram shows a stone suspended under the surface of a liquid from a string. The stone experiences a pressure caused by the
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