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Ulleksa [173]
4 years ago
10

What does Kepler's first law of planetary motion imply?

Physics
1 answer:
BlackZzzverrR [31]4 years ago
6 0

<u>Answer:</u>

The correct answer option is D.  The distance between the planet and the Sun changes as the planet orbits the sun.

<u>Explanation:</u>

Kepler’s laws of planetary motion, derived by the German astronomer Johannes Kepler, are the laws of physics that describe the motions of the planets in the solar system.

According to the Kepler's first law of planetary motion: the path on which the planets orbit around the sun is elliptical in shape, with the center of the sun at one focus.

Therefore, the distance between the Sun and the planets vary as the planet orbit around the sun.

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Leta stetter hollingworth conducted pioneering work on __________. a. identity development in ethnic minorities b. cognitive pro
Elena L [17]

D.  Leta stetter hollingworth conducted pioneering work on <u>adolescent development and gifted children</u>.

<h3>Who is Leta stetter hollingworth?</h3>

Leta stetter hollingworth is an early feminist and active member of the Women's Suffrage Party.

Leta Stetter Hollingworth is best known for her landmark contributions to the psychology of women and to education of the gifted. That is adolescent development and gifted children.

Thus, we can conclude that Leta stetter hollingworth conducted pioneering work on <u>adolescent development and gifted children</u>.

Learn more about Leta stetter hollingworth here: brainly.com/question/2680369

#SPJ1

4 0
1 year ago
"On a movie set, an alien spacecraft is to be lifted to a height of 32.0 m for use in a scene. The 260.0-kg spacecraft is attach
Lisa [10]

Answer:

<em>The time interval required to lift the spacecraft to this specified height is 123.94 seconds</em>

Explanation:

Height through which the spacecraft is to be lifted = 32.0 m

Mass of the spacecraft = 260.0 kg

Four crew member each pull with a power of 135 W

18.0% of the mechanical energy is lost to friction.

work done in this situation is proportional to the mechanical energy used to move the spacecraft up

work done = (weight of spacecraft) x (the height through which it is lifted)

but the weight of spacecraft = mg

where m is the mass,

and g is acceleration due to gravity 9.81 m/s

weight of spacecraft = 260 x 9.81 = 2550.6 N

work done on the space craft = weight x height

==> work = 2550.6 x 32 = 81619.2 J

this is equal to the mechanical energy delivered to the system

18.0% of this mechanical energy delivered to the pulley is lost to friction.

this means that

0.18 x 81619.2  = <em>14691.456 J  </em> is lost to friction.

Total useful mechanical energy =  81619.2 J - 14691.456 J = 66927.74<em> J</em>

Total power delivered by the crew to do this work = 135 x 4 = 540 W

But we know tat power is the rate at which work is done i.e

P = \frac{w}{t}

where p is the power

where w is the useful work done

t is the time taken to do this work

imputing values, we'll have

540 = 66927.74/t

t = 66927.74/540

time taken t = <em>123.94 seconds</em>

8 0
3 years ago
Star a has an absolute magnitude of 8. what is its apparent magnitude at a distance of 100 pc
tresset_1 [31]
From the definition of apparent magnitude, we know that:
m_{1} - m_{2} = -2.5Log( \frac{F_{1}}{F_{2}} )
where:
m = apparent magnitude
F = corresponding flux

We also know that the flux is given by the formula:
F =  \frac{L}{4 \pi  d^{2} }
where:
L = luminosity
d = distance

Therefore:
\frac{F_{1} }{F_{2}} = (\frac{L_{1} }{4 \pi d_{1}^{2} })(\frac{4 \pi d_{2}^{2} }{L_{2} }) \\ =  \frac{L_{1}d_{2}^{2}}{L_{2}d_{1}^{2}}

Now, let's apply these formulae to the same star (therefore, same luminosity), using apparent magnitude and absolute magnitude (which is defined as the apparent magnitude the star would have if it were at a distance of 10pc):
m - M = 2.5 Log ( \frac{d}{10pc})^{2}

Now, let's solve for m:
m = M + 2.5 Log ( \frac{d}{10})^{2}
= <span>8 + 2.5 Log ( \frac{100}{10})^{2}</span>
= 13

Hence, the apparent magnitude of the star would be m = +13
3 0
3 years ago
The symbol for the standard unit of electrical charge is _________.
sertanlavr [38]
Quantity of electrical charge is measured in Coulombs.

The symbol is C.

 b. C
8 0
3 years ago
A 2400-kg satellite is in a circular orbitaround a planet. The
Fofino [41]

Answer

given,

mass of satellite = 2400 Kg

speed of the satellite =  6.67 x 10³ m/s

acceleration of satellite = ?

gravitational force of the satellite will be equal to the centripetal force

F = \dfrac{mv^2}{r}

F = \dfrac{2400\times (6.67\times 10^3)^2}{r}

Assuming the radius of circular orbit = 8.92 x 10⁶ m

now,

F = \dfrac{2400\times (6.67\times 10^3)^2}{8.92\times 10^6}

F = 11970.11 N

acceleration,

a = \dfrac{F}{m}

a = \dfrac{11970.11}{2400}

  a = 4.98 m/s²

4 0
3 years ago
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