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drek231 [11]
3 years ago
10

Which tools would sara us to find an irregularly shaped objects mass and volume A. a meter stick , a ruler , and water

Physics
1 answer:
tester [92]3 years ago
4 0
I think it's D. Usually, to find the volume of an irregularly shaped object, you put it in water with a labeled beaker to measure how much the water rises. The balance would be used to measure the mass in grams.
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Lisette decided to take this game more seriously and put both hands on the rope, applying a 150 N force to the left. Alexis stil
Anni [7]

Answer:

orce or acceleration b. Ms. Sunderland finally decided to take this seriously and put both hands on the rope and applied a 1000 N force to the left, while Jared and James still struggled with their 300 N force to the right. What is ... 150 more force. 10. During 5th period Dylan resisted the forces applied by her classmates in a ...

Explanation:

4 0
3 years ago
A runner of mass 56.0kg runs around the edge of a horizontal turntable mounted on a vertical, frictionless axis through its cent
SCORPION-xisa [38]

Answer: -0.84 rad/sec (clockwise)

Explanation:

Assuming no external torques act on the system (man + turntable), total angular momentum must be conserved:

L1 = L2

L1 = It ω + mm. v . r = 81.0 kg . m2 .21 rad/s – 56.0 kg. 3.1m/s . 3.1 m  

L1 = -521.15 kg.m2/sec (1)

(Considering to the man as a particle that is moving opposite to the rotation of  the turntable, so the sign is negative).

Once at rest, the runner is only a point mass with a given rotational inertia respect from the axis of rotation, that can be expressed as follows:

Im = m. r2 = 56.0 kg. (3.1m)2 = 538.16 kg.m2

The total angular momentum, once the runner has come to an stop, can be written as follows:

L2= (It + Im) ωf = -521.15 kg.m2/sec  

L2= (81.0 kg.m2 + 538.16 kg.m2) ωf = -521.15 kg.m2/sec  

Solving for ωf, we get:

ωf = -0.84 rad/sec  (clockwise)

5 0
3 years ago
A sumo wrestler is 330 pounds. How much force does the earth exert in him? Define Mass Define Weight
Oksana_A [137]

Answer:

a large matters of body with no shape is mass

5 0
3 years ago
A capacitor that is initially uncharged is connected in series with a resistor and a 407.1 Vemf source with negligible internal
Vlad [161]

Answer:

Resistance, R = 478.9 k\ohm

C = 12.95\micro F

Given:

V = 407.1 V

Current through the resistor, I = 0.850 mA = 0.850\times 10^{-3}

Time constant for the circuit, \tau = 6.20 s

Solution:

Initially the capacitor is uncharged, the current in the circuit remains same.

Thus

At t = 0

the current in the circuit, I = \frac{V}{R}

Therefore,

Resistance, R = \frac{V}{I}

R = \frac{407.1}{0.850\times 10^{-3}} = 478.9 k\ohm

Now, for calculation of Capacitance, C:

Time constant for the circuit, \tau = CR

6.20 = C\times 478.9\times 10^{3}

C = 1.295\times 10^{- 5} F = 12.95\micro F

5 0
4 years ago
Mass (kg) Force (N)
Keith_Richards [23]

Answer:B

Explanation:

Acceleration=force/mass

Acceleration=25/5=5

Acceleration=50/10=5

Acceleration=75/15=5

Acceleration=100/20=5

3 0
4 years ago
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